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Lemur [1.5K]
3 years ago
13

Among a student group 49% use Google Chrome, 20% Internet Explorer, 10% Firefox, 5% Mozilla, and the rest use Safari. What is th

e probability that you need to pick 7 students to find 2 students using Google Chrome
Mathematics
1 answer:
Elina [12.6K]3 years ago
8 0

Answer:

17.39%

Step-by-step explanation:

We can summary the question:

  • Probability of students using Google chrome= 0.49
  • Probability of students using other browsers = 0.51

So the probability that you need to pick 7 students to find 2 students using Google Chrome is:

P(G) = C^{7} _{2} * (0.49^{2})(0.51^{7}) = 21*0.2401*0.03 = 0.1739 = 17.39%

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If -1 and 2 are the two zeros of the polynomial x3-4x2-7x+10 find the third zero
rewona [7]

note that the zeroes should be x = 1 and x = - 2 not x = - 1 and x = 2

the factors are then ( x - 1 ) and (x + 2)

and x³ - 4x² - 7x + 10 = (x - 1 )(x + 2) = x² + x - 2

thus x² + x - 2 is a factor

dividing x³ - 4x² - 7x + 10 by x² + x - 2 gives x - 5

the third zero is x = 5

check : (5)³ -4(5)² - 7(5) + 10 = 125 - 100 - 35 + 10 = 0




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Point X is the incenter of ΔABC.
masha68 [24]

Answer:

the first one is 13 and the second is 22

7 0
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How many solutions are<br> there to this system of<br> equations?<br> y = 2x - 1<br> y = 2x + 1
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Answer:

They are 5 I think

Step-by-step explanation:

It should be correct

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Sin^2(alpha) + cos^2(alpha)=? Fast plz sir is asking me rn lol
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4 0
3 years ago
Rectangle A measures 10 inches by 8 inches. Rectangle B is an enlarged copy of Rectangle A. Select all of the measurement pairs
Fudgin [204]

Answer:

See Explanation

Step-by-step explanation:

Given

Rectangle A:

Length: 10\ in

Width: 8\ in

Required

Determine the possible dimensions of Rectangle B

<em>The question has missing options; however, the question can still be solved.</em>

<em></em>

Rectangle B being an enlarged copy of A implies that the dimension of A A is enlarged in equal proportion to form B

Take for instance, the measurements of Rectangle B are

Length: 15 in

Width: 12 in

Divide the corresponding lengths of B by A to get the enlargement ratio

Ratio = \frac{B}{A}

For length:

Ratio = \frac{15}{10}

Ratio = 1.5

For width

Ratio = \frac{12}{8}

Ratio = 1.5

Notice that both ratios are the same.

For this measurement of B, we can conclude that B is an enlargement of A

Assume another measurements for B

Length: 20\ in

Width: 10\ in

Calculate Ratios

Ratio = \frac{B}{A}

For length:

Ratio = \frac{20}{10}

Ratio = 2

For width

Ratio = \frac{10}{8}

Ratio = 1.25

Notice that, both ratios are not equal.

For this measurement of B, we can conclude that B is not an enlargement of A

<em>Conclusively, all you have to do is: determine the ratios of the dimensions of B to A, if the result are equal then B is an enlarged copy of A; if otherwise, then B is not an enlarged copy</em>

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3 years ago
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