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Lemur [1.5K]
3 years ago
13

Among a student group 49% use Google Chrome, 20% Internet Explorer, 10% Firefox, 5% Mozilla, and the rest use Safari. What is th

e probability that you need to pick 7 students to find 2 students using Google Chrome
Mathematics
1 answer:
Elina [12.6K]3 years ago
8 0

Answer:

17.39%

Step-by-step explanation:

We can summary the question:

  • Probability of students using Google chrome= 0.49
  • Probability of students using other browsers = 0.51

So the probability that you need to pick 7 students to find 2 students using Google Chrome is:

P(G) = C^{7} _{2} * (0.49^{2})(0.51^{7}) = 21*0.2401*0.03 = 0.1739 = 17.39%

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USPshnik [31]

Answer: x is less than or equal to -4.25


Step-by-step explanation:

Since the dot on the number line is filled in it is either a less than or equal to or a greater than or equal to. Because the line is going more into negative or descending, it is less than or equal to.

5 0
3 years ago
Read 2 more answers
En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,
Lostsunrise [7]

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

4 0
3 years ago
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Answer: The answer is A

Step-by-step explanation: 4c+6a<120 and 4c+4a<100
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S_A_V [24]

Answer:

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Step-by-step explanation:

3x+6

Factor out 3.

3(x+2)

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The answer i got is b<-18.. i’m not sure if it’s right but you could try ! :).. i’m very sorry if you get it wrong .
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