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3 years ago

The two triangles are similar. Solve for x.

Mathematics

1 answer:

Alenkasestr [34]3 years ago

5 0

Answer:

Here Two triangles BDE and BAC are similar as mentioned

So, According to Similarity of triangles theorem

BE/BC = DE/AC

4/16= x/20

1/4 = x/20

x= 20/4

x=5

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Find the equation of the line in slope-intercept form (-1,-1) and (1,0)

ArbitrLikvidat [17]

Answer:

An equation in slope-intercept form of the line will be

$y\:=\frac{1}{2}x-\frac{1}{2}$

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where m is the slope and b is the y-intercept

Given the points

(-1, -1)

(1, 0)

Finding the slope between (-1,-1) and (1,0)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-1,\:-1\right),\:\left(x_2,\:y_2\right)=\left(1,\:0\right)$

$m=\frac{0-\left(-1\right)}{1-\left(-1\right)}$

$m=\frac{1}{2}$

substituting m = 1/2 and (-1, -1) in the slope-intercept form of the line equation to determine the y-intercept

$y = mx+b$

$-1=\frac{1}{2}\left(-1\right)+b$

$-\frac{1}{2}+b=-1$

Add 1/2 to both sides

$-\frac{1}{2}+b+\frac{1}{2}=-1+\frac{1}{2}$

$b=-\frac{1}{2}$

substituting m = 1/2 and b = -1/2 in the slope-intercept form of the line equation

$y = mx+b$

$y\:=\frac{1}{2}x+\left(-\frac{1}{2}\right)$

$y\:=\frac{1}{2}x-\frac{1}{2}$

Therefore, an equation in slope-intercept form of the line will be

$y\:=\frac{1}{2}x-\frac{1}{2}$

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2 years ago

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3 years ago