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2 years ago

The height of a triangle is twice the length of its base. The

Mathematics

1 answer:

lions [1.4K]2 years ago

6 0

Answer:

height = 14.2 m , base = 7.1 m

Step-by-step explanation:

let the base be b then height h = 2b

The area (A) of a triangle is calculated as

A = $\frac{1}{2}$ bh

Here A = 50 , then

$\frac{1}{2}$ × b × 2b = 50

b² = 50 ( take square root of both sides )

b = $\sqrt{50}$ ≈ 7.1 ( to the nearest tenth )

Then base = 7.1 m and height = 2 × 7.1 = 14.2 m

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Staci has seven more cats than Taylor. Write an expression that illustrates how many cats Staci has. Use X to represent the numb

Tanzania [10]

Answer:

x + 7

Step-by-step explanation:

If the amount of cats Taylor has is x and Staci has 7 more cats you are basically adding 7

so since The amount of Taylor's cats are x and you are adding 7 it would be written as

x+7

8 0

2 years ago

6+2x+4(x+5) <br><br><br><br> Please ASAP and you get points b

Zanzabum

Factor is 2(13+3x)
Simplify is 26+6x

6 0

2 years ago

Evaluate the upper and lower sums for f(x) = 1 + x2, −1 ≤ x ≤ 1, with n = 3 and 4.

Elenna [48]

I'm going to assume that your function is f(x) = 1 + x^2 (NOT x2).

I suspect you're trying to estimate the "area under the curve of f(x) = 1 + x^2. You need to use this or a similar description to explain what you're doing.

Also, you need to specify whether you want "left end points" or "right end points" or "midpoints." Again I must assume you want one or the other (and will assume that you meant "left end points").

First, let's address the case n=3. You must graph f(x) = 1 + x^2 between -1 and +1. We will find the "lower sum," using "left end points." The 3 x-values are {-1, -1/3, 1/3}. Evaluate the function f(x) = 1 + x^2 at these 3 x-values. Keep in mind that the interval width is 2/3.
The function (y) values are {0, 2/3, 4/3}.

Sorry, Michael, but I must stop here and await clarification from you regarding what you've been told to do in this problem. Otherwise too much guessing (regarding what you meant) is necessary. Please review the original problem and ensure that you have copied it exactly as presented, and also please verify whether this problem does indeed involve estimating areas under curves between starting and ending x-values.

7 0

3 years ago

Please answer: what is the quotient? what is the remainder?

stepladder [879]

Quotient : 5x + 8 Remainder : 14x2 + 5x + 11

3 0

3 years ago

In a study of the accuracy of fast food drive-through orders, Restaurant A had 229229 accurate orders and 7070 that were not ac

tiny-mole [99]

Answer:

a) 90% Confidence interval for true proportion of orders that are not accurate

= (0.194, 0.274)

In percentage terms, (19.4%, 27.4%)

b) Since the two confidence intervals overlap, neither restaurant appears to have a significantly different percentage of orders that are not accurate.

Step-by-step explanation:

a) Confidence Interval for the population proportion of orders that are not accurate is basically an interval of range of values where the true population proportion of orders that are not accurate can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample proportion) ± (Margin of error)

Sample proportion of orders that were not accurate = 70 ÷ (70 + 229) = 0.2341

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error)

Critical value at 90% confidence interval for sample size of (70+229=299) is obtained from the z-tables because although, the population standard deviation is not known, the sample size is large enough.

Critical value = 1.645 (from the z-tables)

Standard error of the mean = σₓ = √[p(1-p)/N]

p = sample proportion of orders that are not accurate = 0.2341

n = sample size = 299

σₓ = √(0.2341×0.7659/299) = 0.02449

95% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

CI = 0.2341 ± (1.645 × 0.02449)

CI = 0.2341 ± 0.04028

90% CI = (0.19382, 0.27438)

90% Confidence interval = (0.194, 0.274)

b) Confidence Interval for true proportion of orders that are not accurate

For Restaurant A = (0.194, 0.274)

For Restaurant B = (0.216, 0.297)

There is overlap. For example, p = 0.235 is possible for both intervals, which means that both restaurants could have a 23.5% inaccuracy rate. If there was no overlap of the intervals, then it would be impossible for p to be the same value for both restaurants. So again, we could conclude that the restaurants could have the same inaccurate order rate due to the overlap. There just isn't enough evidence to suggest that the true percentage of orders that are not accurate for the 2 restaurants are very different.

Hope this Helps!!!

5 0

3 years ago