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Slav-nsk [51]
3 years ago
12

Factor completely

Mathematics
1 answer:
luda_lava [24]3 years ago
4 0

Answer:

B)

B)

D)

Step-by-step explanation:

1. 7x^3y+14x^2y^3-7x^2y^2

The GCF of all the term of the above polynomial is 7x^2y , hence we take it outside and form a bracket

7x^2y(x+2y^2-y)

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

2. 5x(x+3)+6(x+3)

The GCF of all the term of the above polynomial is (x+3) , hence we take it outside and form a bracket

(x+3)(5x+6)

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

3. 8x^5+2x^4+4x^2

The GCF of all the term of the above polynomial is 2x^2 , hence we take it outside and form a bracket

2x^2(4x^3+x^2+2)

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (D) is the right answer

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lisov135 [29]
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Multiply -1 by the (4)/(cotx) inside the parentheses. 

4tan^(2)x-(4)/(cotx)+sinxcscx 


To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is cotx. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. 


4tan^(2)x*(cotx)/(cotx)-(4)/(cotx)+sin... 


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Combine the numerators of all expressions that have common denominators. 
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(4tan^(2)xcotx-4+cotxsinxcscx)/(cotx)</span>
8 0
2 years ago
One step inequalities
pishuonlain [190]
Whats the question ? 
3 0
3 years ago
X + 7 &lt; 15<br> I need to know what this answer is and quick
sergij07 [2.7K]

Answer:

x<8

Step-by-step explanation:

x+7<15

x<15-7

x<8

hope \: it \: helps

4 0
3 years ago
Which expressions are equivalent to -3(2+7) A: -6+21 or B:-21+6​
Neporo4naja [7]

<u>Answer:</u>

None

<u>Explanation:</u>

-3(2+7) = -3×9 = -27

-6+21 = 15

-21+6​ = -15

Hence there is no equivalence

3 0
3 years ago
HELP i’m having trouble with my homework assignments
Aleksandr-060686 [28]

Answer:

Collin: about $401 thousand

Cameron: about $689 thousand

Step-by-step explanation:

A situation in which doubling time is constant is a situation that can be modeled by an exponential function. Here, you're given an exponential function, though you're not told what the variables mean. That function is ...

P(t)=P_0(2^{t/d})

In this context, P0 is the initial salary, t is years, and d is the doubling time in years. The function gives P(t), the salary after t years. In this problem, the value of t we're concerned with is the difference between age 22 and age 65, that is, 43 years.

In Collin's case, we have ...

P0 = 55,000, t = 43, d = 15

so his salary at retirement is ...

P(43) = $55,000(2^(43/15)) ≈ $401,157.89

In Cameron's case, we have ...

P0 = 35,000, t = 43, d = 10

so his salary at retirement is ...

P(43) = $35,000(2^(43/10)) ≈ $689,440.87

___

Sometimes we like to see these equations in a form with "e" as the base of the exponential. That form is ...

P(t)=P_{0}e^{kt}

If we compare this equation to the one above, we find the growth factors to be ...

2^(t/d) = e^(kt)

Factoring out the exponent of t, we find ...

(2^(1/d))^t = (e^k)^t

That is, ...

2^(1/d) = e^k . . . . . match the bases of the exponential terms

(1/d)ln(2) = k . . . . . take the natural log of both sides

So, in Collin's case, the equation for his salary growth is

k = ln(2)/15 ≈ 0.046210

P(t) = 55,000e^(0.046210t)

and in Cameron's case, ...

k = ln(2)/10 ≈ 0.069315

P(t) = 35,000e^(0.069315t)

5 0
3 years ago
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