I need help with my math problem #6
1 answer:
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Answer: 0.475 cups of broth per serving.
Explanation:
1) Ratio given:
i) To facilitate the operations, transform the mixed number 4 3/4 cups into improper fraction:
4 + 3/4 = [16 + 3] / 4 = 19 / 4
ii) ratio broth: servings
2) Proportion with the unknown number of cups of broth per serving:
3) Solve for the unknown:
x = [19 / 4] cups × 1 serving / 10 servings = 19 / 40 cups = 0.475 cups
Explanation:
1) Ratio given:
i) To facilitate the operations, transform the mixed number 4 3/4 cups into improper fraction:
4 + 3/4 = [16 + 3] / 4 = 19 / 4
ii) ratio broth: servings
2) Proportion with the unknown number of cups of broth per serving:
3) Solve for the unknown:
x = [19 / 4] cups × 1 serving / 10 servings = 19 / 40 cups = 0.475 cups
<u>EXPLANATION</u><u>:</u>
In ∆ ABC , ∠ABC = 40°
- ∠CAB = x°
- & ∠ACD = 50°
∠ACD is an exterior angle formed by extending BC to D
We know that
The exterior angle of a triangle formed by extending one side is equal to the sum of the opposite interior angles.
∠ACD = ∠CAB + ∠ABC
⇛50° = x° + 40°
⇛x° = 50°-40°
<h3>⇛x° = 10°</h3>and
In ∆ ACD , AC = CD
⇛ ∠CDA = ∠CAD
Since the angles opposite to equal sides are equal.
Let ∠CDA = ∠CAD = A°
We know that
The sum of all angles in a triangle is 180°
In ∆ ACD,
∠CDA +∠CAD + ∠ACD = 180°
A°+A°+50° = 180°
⇛2A°+50° = 180°
⇛2A° = 180°-50°
⇛2A° = 130°
⇛A° = 130°/2
⇛A° = 65°
now,
∠CDA = ∠CAD = 65°
∠BAC + ∠CAD+y = 180°
Since angles in the same line
10°+65°+y = 180°
⇛75°+y =180°
⇛y = 180°-75°
<h3>⇛y = 105°</h3><u>Answer</u><u>:</u> Hence, the value of “x” & “y” will be 10° and 105° respectively.
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Answer:
(d) one output for every input
Step-by-step explanation:
A function is 1-to-1 if its graph passes the horizontal line test: a horizontal line may intersect the graph in only one place.
