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evablogger [386]
3 years ago
15

Plz help hurry it’s on the pic plz

Mathematics
1 answer:
Margaret [11]3 years ago
4 0

Answer:2 for both

Step-by-step explanation: because 4x3/5 is 2.4 converted to a fraction 2 4/10 simplified 2 2/5 the equal sign is telling you what it equals you do so and it's 2 2/5

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PLease answer as soon as possible
yulyashka [42]

Answer:

No

Step-by-step explanation:

Every x value in the domain should only have 1 y value. In the graph, for x=5 (the input) there are 2 y values (6 and -6) so this is not a function.

3 0
3 years ago
Read 2 more answers
Find the value of x in the equation 3(2x-4)-5(x-2)=1
Lyrx [107]

Answer:

x=3

Step-by-step explanation:

3(2x−4)−5(x−2)=1

Step 1: Simplify both sides of the equation.

3(2x−4)−5(x−2)=1

(3)(2x)+(3)(−4)+(−5)(x)+(−5)(−2)=1(Distribute)

6x+−12+−5x+10=1

(6x+−5x)+(−12+10)=1(Combine Like Terms)

x+−2=1

x−2=1

Step 2: Add 2 to both sides.

x−2+2=1+2

x=3

4 0
2 years ago
The function f(x) = x2 + 6x + 3 is transformed such that g(x) = f(x − 2). Find the vertex of g(x).
garri49 [273]

Answer:

(-1,-6)

Step-by-step explanation:

f(x)=x^2+6x+3

g(x)=f(x-2)

g(x)=(x-2)^2+6(x-2)+3  (Replaced x in f with (x-2))

g(x)=x^2-4x+4+6x-12+3 (Used (x+b)^2=x^2+2bx+b^2 and distributive property)

g(x)=x^2-4x+6x+4-12+3 (Gathered like terms)

g(x)=x^2+2x-5  (Simplified)

The vertex of a parabola occurs at (\frac{-b}{2a},g(\frac{-b}{2a}).

Let's find \frac{-b}{2a} first.

\frac{-2}{2(1)}=-1

Now we can obtain g(\frac{-b}{2a}) which is g(-1) in this case:

g(x)=x^2+2x-5

g(-1)=(-1)^2+2(-1)-5

g(-1)=1-2-5

g(-1)=-1-5

g(-1)=-6.

The vertex is (-1,-6).

6 0
3 years ago
80% of what(?) games is 32 games..?
exis [7]
Answer=40 games

 32games    x games
________=________
    80%          100%

Cross Multiply
80x=3200
divide both sides by 80
x=40games

80% of 40games is 32 games
3 0
3 years ago
Read 2 more answers
3 lbs of apples cost $9. How many lbs of apples can you get with $12?
qaws [65]
The exact answer is
3.9999999996
but if you round it up it will equal
4
5 0
3 years ago
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