Write an expression that is equivalent to the following: <br><br> x+x+x+x-20

Two of the cards of an ordinary deck of 52 cards are lost. What is the probability that a random card drawn from this (defective

Nostrana [21]

Answer:

0.72

Step-by-step explanation:

Given :Two of the cards of an ordinary deck of 52 cards are lost.

To Find : What is the probability that a random card drawn from this (defective) deck is a spade?

Solution:

Total number of cards = 52

2 cards are lost

Remaining cards = 50

When no spade card is lost

So, No. of spade cards = 13

Total cards = 50

So, probability of getting spade = $\frac{13}{50}$

When 1 spade card is lost

So, No. of spade cards = 12

Total cards = 50

So, probability of getting spade = $\frac{12}{50}$

When 2 spade cards are lost

So, No. of spade cards = 11

Total cards = 50

So, probability of getting spade = $\frac{11}{50}$

So, The he probability that a random card drawn from this (defective) deck is a spade = $\frac{13}{50}+\frac{12}{50}+\frac{11}{50}$

= $\frac{36}{50}$

= [tex]0.72/tex]

Hence the probability that a random card drawn from this (defective) deck is a spade is 0.72

3 0

3 years ago

EXPLAIN YOUR WORK PLZ

trasher [3.6K]

Answer:

D

Step-by-step explanation:

It will be $1,108.0 Because if you devide 40 by the hours, Plus the pay which is 15.40 You will get D

4 0

3 years ago

A manufacturing company employs two devices to inspect output for quality control purposes. The first device is able to accurate

Feliz [49]

Answer:

(a) fxy(x,y) = f(x), f(y)

(b) fx(x) = X = (99.3/100) x 4 = 3.972

(c) E(X) = 4

(d) fy/2y = (99.7/100) of (2 x 4) = 7.976

(e) E(Y | X = 2) = 2.

(f) V(Y | X = 2) = 2

Step-by-step explanation:

fxy(x,y) = f(x), f(y), as the question presented the assumption that the devices are independent, their measurements must also be independent

Since the first device is able to accurately detect 99.3% of the defective items it receives and the total defective items sent is 4,

(b) fx(x) = X = (99.3/100) x 4 = 3.972

(c) E(X) is expected result from first device. It is 4 because the items will be whole number.

(d) fy/2y = (99.7/100) of (2 x 4) = 7.976

(Since the first device is able to accurately detect 99.7% of the defective items it receives and the total defective items sent is 4)

(e) E(Y | X = 2) = 2. If the second device measure 2 defective items (X = 2), first device will also detect 2 because the measure 99.3% and 99.7% accurately. Their measurements will be approximately equal.

f. V(Y | X = 2). Like the explanation for (e) above, any relations V(Y | X = 2) will also be 2

(g) X and Y are independent because the are measure

measurements on two different devices

4 0

3 years ago

What is the greatest common factor of 4xy^2 and 20x^2y^4

AnnyKZ [126]

4xy^2 because 4 and 20's GCF is 4
x and x^2 have X in common
and y^2 and y^4 have y^2 in common
Multiply those together and you get 4xy^2

6 0

3 years ago

Read 2 more answers

30 is what percent of 120?

sergeinik [125]

Answer:

25%

Step-by-step explanation:

30 is what percent of 120

Is means equals

of means multiply

30 = P * 120

Divide by 120 on each side

30/120 = P*120/120

1/4 = P

.25 = P

Now put this in percent form

.25 * 100% = P

25 % = P

6 0

3 years ago

Read 2 more answers

Write an expression that is equivalent to the following: x+x+x+x-20