Given equation is
The given equation is in the form of
a^2= 16 , so a=4
b^2 = 9 so b= 4
The value of 'a' is greater than the value of 'b'
So it is a Horizontal hyperbola
First two graphs are horizontal hyperbola
Here center is (h,k)
h= 5 and k =2 from the given equation
So center is (5,2)
Now we find vertices
Vertices are (h+a,k) and (h-a,k)
We know h=5, k=2 and a=4
So vertices are (9,2) and (1,2)
Second graph having same vertices and center
The correct graph is attached below
Answer: 6y I think. If you would have to add all of the y’s and so you would have 3 y’s and then you add both 3 y’s so 6y
I don’t know if I am right sorry if I’m wrong
#9: 1 and 1 seventh
#10: 1.23
#11: 0.35
<span>The student apparently added numbers without taking into account direction. They seem to have added 15 and 25 and divided by 2 to get the horizontal component of the middle stop when they should have added 15 and -25 and divided by 2. A similar mistake was made on determining the vertical component. The middle stop should have been calculated as 5 blocks west and 7 blocks south of the central station. So your answer is C.</span>
Answer:
Yes it is all correct
Step-by-step explanation:
Good job!!
