I think it’s C. If it is incorrect I apologize.
You would set up equations for both the member and the non-member.
The member's equation would be: 384+8x (x being the number of rounds)
The non-member's equation would be: 48x+24x
then you would set them equal to each other and then solve:
384+8x=48x+24x
384=64x
384/64=x
x=6
they would have to play 6 rounds in order to pay the same amount.
32 Is the answer simple division
Answer:
If you take into account all probabilities, and work on a strategy, rather than individual guesses, you can increase the probability.
Here are the possible outcomes:
BBB
BBR
BRB
BRR
RBB
RBR
RRB
RRR
If you use the strategy:
If a person sees a blue and a red, they pass;
If a person sees a blue and a blue, they guess red;
If a person sees a red and a red, they guess blue;
The probability comes out like this:
(B=blue, R=red, P=pass)
actual guess correct?
BBB RRR no
BBR PPR yes
BRB PRP yes
BRR BPP yes
RBB RPP yes
RBR PBP yes
RRB PPB yes
RRR BBB no
As you can see, this is a 6/8, or 75% chance of being correct.
Answer:
(- 2, 1 ) and (1, 4 )
Step-by-step explanation:
Given the 2 equations
y = - x² + 5 → (1)
- x + y = 3 → (2)
Rearrange (2) expressing y in terms of x by adding x to both sides
y = x + 3 → (3)
Substitute y = x + 3 into (1)
x + 3 = - x² + 5 ( subtract - x² + 5 from both sides )
x² + x - 2 = 0 ← in standard form
(x + 2)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
x - 1 = 0 ⇒ x = 1
Substitute these values into (3) for corresponding values of y
x = - 2 : y = - 2 + 3 = 1 ⇒ (- 2, 1 )
x = 1 : y = 1 + 3 = 4 ⇒ (1, 4 )
