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IrinaVladis [17]
3 years ago
10

If is an angle bisector of ∠QOR and ∠QOP = 71°, then find the angle measure of ∠QOR. Question 8 options: A) 71° B) 142° C) 35.5°

D) 35°
Mathematics
1 answer:
zaharov [31]3 years ago
8 0

Answer:  B. 142°.

Step-by-step explanation:

Given: OP is an angle bisector of ∠QOR and ∠QOP = 71°.

We know that an angle bisector divides an angle into two equal parts.

So, if OP is an angle bisector of ∠QOR and ∠QOP = 71°.

Then, the angle measure of ∠QOR = Twice of ∠QOP

⇒ Angle measure of ∠QOR = 2 (71°)

⇒ Angle measure of ∠QOR = 142°

Hence, correct option is B. 142°.

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The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5
vladimir1956 [14]

Answer:

f=11

Mode=4

Median=4

Explanation:

We are given that

a.Mean of the exam score,\bar x=3.5

Score(x)   frequency   C.F

1                  1                 1

2                  3                4

3                  f                 15(4+f=4+11)

4                  13               28

5                   4               32

\sum f_i=1+3+f+13+4=21+f

\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f

(\bar x)=\frac{\sum f_ix_i}{\sum f_i}

Using the formula

3.5=\frac{79+3f}{21+f}

73.5+3.5f=79+3f

3.5f-3f=79-73.5

0.5f=5.5

f=\frac{5.5}{0.5}=11

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}

Median=\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4

7 0
3 years ago
You have 20 coins valued at 2.60. All are either quarters or nickels. Write and solve a system of equations to find the number o
Ivan

To solve this problem you must apply the following proccedure:

1. You have a total of 21 coins, all nickels and dimes. Then:

x:nickels=5 cents

y: dimes=10 cents

x+y=21

2. You have that the total value is $1.70. Then:

5x+10y=170

3. The system of equation is:

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5x+10y=170    (ii)

4. You have:

x+y=21

x=21-y

5(21-y)+10y=170

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y=13 dimes

x+13=21

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