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IrinaVladis [17]
3 years ago
10

If is an angle bisector of ∠QOR and ∠QOP = 71°, then find the angle measure of ∠QOR. Question 8 options: A) 71° B) 142° C) 35.5°

D) 35°
Mathematics
1 answer:
zaharov [31]3 years ago
8 0

Answer:  B. 142°.

Step-by-step explanation:

Given: OP is an angle bisector of ∠QOR and ∠QOP = 71°.

We know that an angle bisector divides an angle into two equal parts.

So, if OP is an angle bisector of ∠QOR and ∠QOP = 71°.

Then, the angle measure of ∠QOR = Twice of ∠QOP

⇒ Angle measure of ∠QOR = 2 (71°)

⇒ Angle measure of ∠QOR = 142°

Hence, correct option is B. 142°.

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or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1

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