Answer:
V = 36 1/4 in.^3
Step-by-step explanation:
V = LWH
L = 3 5/8 in.
W = 2 1/2 in.
H = 4 in.
V = (3 5/8)(2 1/2)(4) in.^3
Change the mixed numerals to fractions.
<em>To change the mixed numeral a b/c to a fraction, do this: </em>
<em>a b/c = (ac + b)/c</em>
V = (3 * 8 + 5)/8 * (2 * 2 + 1)/2 * 4/1
V = (24 + 5)/8 * (4 + 1)/2 * 4/1
V = 29/8 * 5/2 * 4/1 in.^3
V = 580/16 in.^3
V = 145/4 in.^3
V = 36 1/4 in.^3
Answer:
The average rate of change in the balance over the interval t = 0 to t = 5 is of $20.82 a year. This means that the balance increased by $20.82 a year over the interval t = 0 to t = 5.
Step-by-step explanation:
Given a function y, the average rate of change S of y=f(x) in an interval
will be given by the following equation:

In this problem, we have that:

Find the average rate of change in the balance over the interval t = 0 to t = 5.


Then

The average rate of change in the balance over the interval t = 0 to t = 5 is of $20.82 a year. This means that the balance increased by $20.82 a year over the interval t = 0 to t = 5.
Answer:
A
Step-by-step explanation:
This explanation mostly depends on what you're learning right now. The first way would be to convert this matrix to a system of equations like this.
g + t + k = 90
g + 2t - k = 55
-g - t + 3k = 30
Then you solve using normal methods of substitution or elimination. It seems to me that elimination is the quickest method.
g + t + k = 90
-g - t + 3k = 30
____________
0 + 0 + 4k = 120
4k = 120
k = 30
No you can plug this into the first two equations
g + t + (30) = 90
g + t = 60
and
g + 2t - (30) = 55
g + 2t = 85
now use elimination again by multiplying the first equation by -1
g + 2t = 85
-g - t = -60
_________
0 + t = 25
t = 25
Now plug those both back into one of the equations. I'll just do the first one.
g + (25) + (30) = 90
g = 35
Therefore, we know that Ted spent the least amount of time on the computer.
The second method is using matrix reduction and getting the matrix in the row echelon form, therefore solving using the gauss jordan method. If you would like me to go through this instead, please leave a comment.
Let
x-----> the number of hours that Candice spent doing her homework
y-----> the number of hours that Ronald spent doing his homework
we know that

convert mixed number to an improper fraction

so
-------> equation A
------> equation B
Substitute equation A in equation B

convert an improper fraction to a mixed number

therefore
<u>the answer is the option B</u>

Answer:
The constant of proportionality is 3.
Step-by-step explanation:
6/2 is 3 and so on.
Correct me if I'm wrong