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Lelu [443]
3 years ago
10

The Super Shop and Save store had 120 gallons of milk placed on the shelf one night. During the next morning's inspection, the m

anager found 15% of the milk had
passed expiration date. How many gallons of milk had passed the expiration date
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
8 0
18 gallons of milk had passed the expiration date.

Explanation step by step

Multiply 120x 15%
Turn 15% into a decimal which is 0.15 so now it’s 120x0.15 which equals to 18.
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1/2x-5>-7 how do I solve this linear inequality
Tems11 [23]

1/2x-5>-7\\1/2*x-5>-7\\1/2*x>-7+5\\1/2*x>-2\\x>-2/(1/2)\\x>-2*2\\x>-4

8 0
3 years ago
F(x)=8x +5, which function represents f(e-9)
Ronch [10]

Answer:

f(e - 9) = 8e - 67

Step-by-step explanation:

To evaluate f(e - 9) substitute x = e - 9 into f(x)

f(e - 9) = 8(e - 9) + 5 = 8e - 72 + 5 = 8e - 67

7 0
3 years ago
Please help me because I don't understand how to do it.:)
shutvik [7]

Answer:

y= 1/3 x +5

Step-by-step explanation:

To find the slope, we take two points

(0,5)   and (15,10)

The slope is found by the formula

m = (y2-y1)/ (x2-x1)

   = (10-5)/(15-0)

   = 5/15

   = 1/3

The slope is 1/3

The y intercept is found when x=0

When x=0  y=5

The slope intercept form of the line is

y=mx+b  where m is the slope and b is the y intercept

y= 1/3 x +5

3 0
3 years ago
Choose the equation below that represents the line that passes through the point (7, -2) and has a slope of -3
Ray Of Light [21]

Answer:

B

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - 3 and (a, b) = (7, - 2 ), thus

y - (- 2) = - 3(x - 7) , that is

y + 2 = - 3(x - 7) → B

3 0
2 years ago
Read 2 more answers
3x to the power of 3 + 21x squared + 36x = 0 by factoring the quadratic equation.
Diano4ka-milaya [45]

Answer:

x = 0, -4 and -3.

Step-by-step explanation:

The given expression is "3x to the power of 3 + 21x squared + 36x = 0".

We can write this expression as follows :

3x^3+21x^2+36x=0

Taking 3x common.

3x(x^2+7x+12)=0\\\\3x=0\ \text{and}\ (x^2+7x+12)=0

x = 3

x^2+7x+12=0\\\\x^2+3x+4x+12=0\\\\x(x+3)+4(x+3)=0\\\\(x+4)(x+3)=0\\\\x=-4,-3

Hence, the solution of the given quadratic equation are x = 0, -4 and -3.

5 0
3 years ago
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