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avanturin [10]
3 years ago
15

At 10:30am,a submarine was 43 feet below the ocean surface.By10:45am,it was 271 feet below the surface. How much did it descend

in that 15 minutes?
Mathematics
1 answer:
matrenka [14]3 years ago
4 0

Hi!

Your answer would be:<em> 228ft below the ocean surface.</em>

Reason being: <em>when you subtract 43 from 271, you get 228.</em>

Hope this helps!

If you need anymore help, please let me know!

<em>Yours Truly,</em>

<h2><em>~~~PicklePoppers~~~</em></h2>
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Substitute in the values of both given coordinates & form 2 equations:

\left \{ {{A(2)+B(-1)=1} \atop {A(-3)+B(-2)=1}} \right. \\\\=\left \{ {{2A-B=1} \atop {-3A-2B=1}} \right.

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2A-B=1\\-B=1-2A\\B=2A-1

Substitute in the B-value to the other equation:

-3A-2B=1\\-3A-2(2A-1)=1\\-3A-4A+2=1\\-7A=1-2\\-7A=-1\\A=\frac{-1}{-7} =\frac{1}{7}

Find the B-value using the equation from before:

B=2A-1=2(\frac{1}{7})-1=\frac{2}{7} -\frac{7}{7} =-\frac{5}{7}  

Therefore the equation Ax + By = 1 would equal:

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