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Umnica [9.8K]
3 years ago
6

What quadrant would the ordered pair -4,-6 fall in​

Mathematics
1 answer:
quester [9]3 years ago
8 0

Answer:

y = x (2) + 10 x + 24

Step-by-step explanation:

quadrent 3

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Kyung works 5 hours at a restaurant each Wednesday. He also earns $37 a week delivering newspapers. Kyung makes a total of $79.5
lyudmila [28]

Answer:

The answer is 5 m + 37 = 79.50

Step-by-step explanation:

You want to multiply 5 and m because m represents the amount he makes each hour and he works 5 hours each Wednesday. Then you add that to 37 to get $79.50.

4 0
3 years ago
Write an inequality for the graph. Then, in words, describe all the values of that make the inequality true.
kow [346]
-3 > x

The values that make this inequality true are those that are less than -3. The inequality does not include -3.
7 0
2 years ago
A car travels at a constant speed of 65 miles per hour. The distance the car travels in Miles d, which is a function of time, t.
PolarNik [594]

Answer:

  t(d) = d/65

Step-by-step explanation:

To solve for t, divide by its coefficient:

  d = 65t

  d/65 = 65t/65 . . divide* by 65

  d/65 = t . . . . . . . simplify

Then you can write it in function form if you like:

  t(d) = d/65

_____

* Of course, the rules of equality say you must divide <em>both sides</em> of the equation by the same number.

4 0
3 years ago
Read 2 more answers
Isolate the variable x to solve the inequality. x +5&gt;10
Natalka [10]

Answer:

\boxed{\ x>5 \ }

Step-by-step explanation:

x+5 > 10

<=>

x+5-5 > 10-5

<=>

x > 5

hope this helps

6 0
3 years ago
Find the volume of the following solid. Using cylindrical coordinates
Reika [66]

In cylindrical coordinates, the equations of the surfaces become

z = 4 - 4r^2 \\\\ z = (r^2)^2 - 1 = r^4 - 1

These surfaces intersect on the cylinder of radius 1 with cross sections parallel to the x,y-plane:

4 - 4r^2 = r^4 - 1 \\\\ \implies r^4 + 4r^2 - 5 = (r-1)(r+1)(r^2+5) = 0 \\\\ \implies r=1

Then in cylindrical coordinates, the volume of the space bounded by these surfaces is

\displaystyle \int_0^{2\pi}\int_0^1\int_{r^4-1}^{4-4r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta = 2\pi \int_0^1 \int_{r^4 - 1}^{4-4r^2}r\,\mathrm dz\,\mathrm dr \\\\ = \pi \int_0^1 (4-4r^2)^2 - (r^4-1)^2 \,\mathrm dr \\\\ = \pi \int_0^1 (15-32r^2+18r^4-r^8)\,\mathrm dr = \boxed{\frac{352\pi}{45}}

7 0
3 years ago
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