bearing in mind that an absolute value expression is in effect a piece-wise expression, because it has a ± version.
![\bf 3|x|+7=28\implies 3|x|=21\implies |x|=\cfrac{21}{3}\implies |x|=7\implies \begin{cases} +(x)=7\\ -(x)=7 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ +(x)=7\implies \boxed{x=7}~\hfill -x=7\implies \boxed{x=-7}](https://tex.z-dn.net/?f=%20%5Cbf%203%7Cx%7C%2B7%3D28%5Cimplies%203%7Cx%7C%3D21%5Cimplies%20%7Cx%7C%3D%5Ccfrac%7B21%7D%7B3%7D%5Cimplies%20%7Cx%7C%3D7%5Cimplies%20%20%5Cbegin%7Bcases%7D%20%2B%28x%29%3D7%5C%5C%20-%28x%29%3D7%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%2B%28x%29%3D7%5Cimplies%20%5Cboxed%7Bx%3D7%7D~%5Chfill%20%20-x%3D7%5Cimplies%20%5Cboxed%7Bx%3D-7%7D%20)
Answer:
52 miles
Step-by-step explanation:
A to B:
sqrt( (3 - (-2))^2 + (-11 - 1)^2 )
sqrt( (5)^2 + (-12)^2 )
sqrt( 25 + 144 )
sqrt( 169 )
13
B to C:
sqrt( (-2 - 3)^2 + (-23 - (-11))^2 )
sqrt( (-5)^2 + (-12)^2 )
sqrt( 25 + 144 )
sqrt( 169 )
13
C to D:
sqrt( (-7 - (-2))^2 + (-11 - (-23))^2 )
sqrt( (-5)^2 + (12)^2 )
sqrt( 25 + 144 )
sqrt( 169 )
13
D to A:
sqrt( (-2 - (-7))^2 + (1 - (-11))^2 )
sqrt( (5)^2 + (12)^2 )
sqrt( 25 + 144 )
sqrt( 169 )
13
Adding:
13 + 13 + 13 + 13
52
18/90
Divide by the common factor of 18 and 90, 9.
(18/9) / (90/9)
2/10
Divide top and bottom by 2
1/5
Hope this helps :)
Answer:
Step-by-step explanation: idk
