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svp [43]
3 years ago
12

Which of the following expressions is equal to -3x^2-12??!!! please help him

Mathematics
1 answer:
Andreyy893 years ago
3 0

Answer:

-3 ( x+2i) (x-2i)

Step-by-step explanation:

-3x^2-12

Factor out a -3

-3(x^2 +4)

Rewrite

-3 ( x^2 - -4)

-3 ( x^2 - (-2i)^2)  This is the difference of squares ( a^2 -b^2 ) = (a-b)(a+b)

-3 ( x- -2i) (x+2i)

-3( x+2i) (x-2i)

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Five buckets all had different amounts of water in them. tom poured all the water together and divided the water equally among t
guajiro [1.7K]

(A) Mean best describes the amount of water in each bucket.

<h3>What is mean?</h3>
  • A dataset's mean (also known as the arithmetic mean, as opposed to the geometric mean) is the sum of all values divided by the total number of values.
  • It is the most widely used measure of central tendency and is frequently referred to as the "average."
  • In mathematics, particularly statistics, there are several types of means.
  • Each mean is used to summarize a specific set of data, often in order to better understand the overall value (magnitude and sign) of a given data set.
  • In two simple steps, we can calculate the mean or average of a data set: add up all of the values to find the sum.
  • Subtract the sum from the total number of values in the data set.

Therefore, (A) mean best describes the amount of water in each bucket.

Know more about mean here:

brainly.com/question/1136789

#SPJ4

The correct question is given below:
Five buckets each had different amounts of water in them. Tom poured all of the water together and then divided the water equally among the buckets. Which term best describes the amount of water in each bucket?

A. mean

B. range

C. outlier

D. mean absolute deviation

8 0
2 years ago
Find the area of the region in the first quadrant bounded on the left by the ​y-​axis, below by the line y equals one third x co
bonufazy [111]

Answer:

The bounded area  is: \frac{73}{6}\approx 12.17

Step-by-step explanation:

Let's start by plotting the functions that enclose the area, so we can find how to practically use integration. Please see attached image where the area in question has been highlighted in light green. The important points that define where the integrations should be performed are also identified with dots in darker green color. These two important points are: (2, 6) and (3, 1)

So we need to perform two separate integrals and add the appropriate areas at the end. The first integral is that of the difference of function y=x+4 minus function y=(1/3)x , and this integral should go from x = 0 to x = 2 (see the bottom left image with the area in red:

\int\limits^2_0 {x+4-\frac{x}{3} } \, dx =\int\limits^2_0 {\frac{2x}{3} +4} \, dx=\frac{4}{3} +8= \frac{28}{3}

The next integral is that of the difference between y=-x^2+10 and the bottom line defined by: y = (1/3) x. This integration is in between x = 2 and x = 3 (see bottom right image with the area in red:

\int\limits^3_2 {-x^2+10-\frac{x}{3} } \, dx =-9+30-\frac{3}{2} -(-\frac{8}{3} +20-\frac{2}{3} )=\frac{39}{2} -\frac{50}{3} =\frac{17}{6}

Now we need to add the two areas found in order to get the total area:

\frac{28}{3} +\frac{17}{6} =\frac{73}{6}\approx 12.17

8 0
3 years ago
2. Your doctor prescribes you a new medicine that
givi [52]

Answer:

I'm guessing 125 millegrams.

4 0
3 years ago
What is the volume of this?
Vsevolod [243]

Answer:

c

Step-by-step explanation:

3 0
2 years ago
Jan worked 38 h last week. she worked four times as many 8-hour shifts as 6-hour shifts. how many 8-hour shifts did she work?
Aleksandr [31]
8x + 6y = 38

x = 4y

substituting for x in the first equation:-

8(4y) + 6y = 38
38y = 38 
y = 1

therefore x = 4(1) = 4

She worked 4 8-hr shifts and 1 6-hr shift  Answer
5 0
4 years ago
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