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Xelga [282]
3 years ago
12

What's the x plz help

Mathematics
1 answer:
slavikrds [6]3 years ago
5 0

Answer:

The answer for x is ten

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What is the relationship between the 4s in the number 4498
algol13
The 4 in the thousands place is 10 times the 4 in the hundreds place.
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Change 43% into a decimal number
Softa [21]
To make a percent to a decimal, move the decimal to the left 2 times. 
43%=0.43
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A professor determined the relationship between the time spent studying (in hours) and performance on an exam.
kykrilka [37]
Step 1: Insert 2.6 hours for the variable of time and solve.
70.443 + 4.885(2.6)
70.443+ 12.701
= 83.144
This is Ann's EXPECTED exam score.  Because of the concert, Ann scored 16 points lower than this number.
Step 2: Subtract 16 from Ann's expected score.
83.144 - 16
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3 0
3 years ago
A survey found that​ women's heights are normally distributed with mean 63.2 in. and standard deviation 2.4 in. The survey also
Effectus [21]

Answer: 99.51%

Step-by-step explanation:

Given : A survey found that​ women's heights are normally distributed.

Population mean : \mu =63.2  \text{ inches}

Standard deviation: \sigma= 2.4\text{ inches}

Minimum height = 4ft. 9 in.=4\times12+9\text{ in.}=57\text{ in.}

Maximum height = 6ft. 2 in.=6\times12+2\text{ in.}=74\text{ in.}

Let x be the random variable that represent the women's height.

z-score : z=\dfrac{x-\mu}{\sigma}

For x=57, we have

z=\dfrac{57-63.2}{2.4}\approx-2.58

For x=74, we have

z=\dfrac{74-63.2}{2.4}\approx4.5

Now, by using the standard normal distribution table, we have

The probability of women meeting the height requirement :-

P(-2.58

Hence, the percentage of women meeting the height requirement = 99.51%

8 0
3 years ago
Please help me. I need help please.
Mice21 [21]

Answer:

The correct options are;

EFGH has 4 congruent sides

Diagonal FH bisects angles EFG and EHG

Angle FEH is congruent to angle FGH

Step-by-step explanation:

1) Given that for a reflection, we have;

The distance of the reflected preimage from the line of reflection = The distance of the reflected image from the line of reflection

Therefore;

The distance of the point E from the line HF = The distance of the point G from the line HF

Also the reflection of an preimage (x, y) about the x-axis, gives an image (x, -y)

We can show that from the length of a line given by the equationl = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}, that the length EH ≅ GH and EF ≅ GF

Therefore since we are given that EH = EF, we have;

EH = GH = GF = EF by the definition of congruency, which gives 4 congruent sides

2) Given that EH = GH = GF = EF and HF = FH by reflective property, we have;

ΔEHF ≅ ΔGHF

∴ ∠GHF ≅ ∠EHF by Congruent Parts of Congruent Triangles are Congruent

Similarly, ∠GFH ≅ ∠EFH

Therefore, ∠GFH = ∠EFH and ∠GHF = ∠EHF

Therefore, diagonal FH bisects angles EFG and EHG

3) Given that ΔEHF ≅ ΔGHF, we have;

Angle FEH is congruent to angle FGH, by Congruent Parts of Congruent Triangles are Congruent

7 0
3 years ago
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