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oee [108]
3 years ago
12

Which expression is 5 times as large as the expression 345+23

Mathematics
2 answers:
anyanavicka [17]3 years ago
6 0

Answer: 1840

Step-by-step explanation:

you add 345 + 23 and multiply by 5

natima [27]3 years ago
3 0

Answer:

1840

Step-by-step explanation:

345+23=368*5

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Mrs. Oliver drew a box plot to represent her students’ scores on a mid-term test.
Rzqust [24]

Answer:

About 1/4 scored higher and 3/4 scored lower

Step-by-step explanation:

84 is on the right side line

Each line represents 25 % of the score

It is 75 percent ( 3 lines) of the way

She scored higher than 75% of the students and lower than 25% of the students

About 1/4 scored higher and 3/4 scored lower

6 0
2 years ago
how many ninths does it take to make the same amount as 1/3.Explain your answer in words and pictures
docker41 [41]
The answers is 3/9 which you can check by reducing.  It reduces to 1/3.  Basically you go 1/3 = x/9 then cross multiple to get 9=3x do the division so 3x/3 and 9/3 and you get 3/9.
5 0
3 years ago
Solve the system of equations -2x+y=5 x-3y=-30
EastWind [94]
-2x+y=5
x-3y=-30 so you can multiply the bottom equation by 2 you'll get 2x-6y=-60

-2x+y=5
2x-6y=-60 And subtract the equations. You'll get -5y=-55 y=11. Plug it in to one of the original equations. -2x+(11)=5 
-2x=-6 so x=3 

y=11 and x=3 
5 0
3 years ago
What’s the awnser to this mathematics equation
Anestetic [448]

Answer:

Half of 9

So 4.5

6 0
3 years ago
Read 2 more answers
g Let G be a not necessarily abelian group with normal subgroups H and K such that H contains K (i.e., K ✂ G, H ✂ G, K ≤ H) and
allsm [11]

Answer:

Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, [ab]_K is equal to [ba]_K, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.

Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, [ab]_H = [ba]_H . Since a and b were generic elements of H, then H/G is abelian.

4 0
3 years ago
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