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Elan Coil [88]
3 years ago
7

Given that 4 x : 3 = 11 : 7 Calculate the value of x .

Mathematics
1 answer:
Airida [17]3 years ago
3 0

Step-by-step explanation:

4x/3=11/7

4x=11×3/7?

4x=33/7

4x=4.7

x=4.7/4

x=1.175

please mark mean as brilliant brainliest

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ra1l [238]

Answer:

1.9 Kilograms.

Step-by-step explanation

To find the total, subtract 35 and 44, that equals 9. so take 35 from 44, Thats 1 kilo, plus the 9 extra. 1.9 Kilos

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3 years ago
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Given f of x equals 5 times x minus 6 for x less than 3, equals x squared for x between 3 and 5 inclusive, and equals 2 times x
konstantin123 [22]

Answer:

<em>D. 5 for x less than or equal to 4, equals 2x for x between 4 and 6 including 6, and equals 4 for x greater than 6 Domain: All real number</em>s.

Step-by-step explanation:

Find the complete diagram attached

First we need to get the derivative of the functions

For the function f(x) = 5x - 6

Using the formula

If f(x) = axⁿ

f'(x) = naxⁿ⁻¹

For the function f(x) = 5x - 6

f'(x) = 1(5)x¹⁻¹

f'(x) = 5x⁰

f'(x) = 5

For the function f(x) =x²-2

f'(x) = 2x²⁻¹

f'(x) = 2x

For the function f(x) = 4x+10

f'(x) = 1(4)x¹⁻¹

f'(x) = 4x⁰

f'(x) = 4

Get the domain

The domain is the value of the input variable x for which the functions exists. For the functions given, the domain will be on all real numbers i.e the functions will exists for any value of x on the number line.

Hence Option D is correct

7 0
3 years ago
Can lettuce leave be measured in grams
Dahasolnce [82]
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3 years ago
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2 years ago
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Eduardwww [97]

Answer:

The Company AB must sell 116 computers to break even

Step-by-step explanation:

we have

R(x)=1.5x -----> equation A

C(x)=145+\frac{1}{4}x ----> equation B

where

C is the cost function

R is the revenue function

x is the number of computers sold

we know that

Break even is when the cost is equal to the revenue

so

equate equation A and equation B

1.5x=145+\frac{1}{4}x

Solve for x

subtract 1/4x both sides

1.5x-\frac{1}{4}x=145

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x=116

therefore

The Company AB must sell 116 computers to break even

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