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3 years ago

PLEASE HELP ME GUYS!!!

Mathematics

2 answers:

grandymaker [24]3 years ago

8 0

The answer is b hope it help

pashok25 [27]3 years ago

6 0

((((((((((B)))))))))

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Ana earns 75 points and loses 30 points write and solve an expression to find anas final score

steposvetlana [31]

75-30=
ana would have 45 points

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4 years ago

Anna wants to buy a car in two years and wants to have $10,000 for the purchase. How much will Anna need to deposit today in an

Brut [27]

Answer:

Anna will need to deposit $\$9,050.25$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=2\ years\\A=\$10,000\\ r=0.05\\n=12$

substitute in the formula above and solve for P

$10,000=P(1+\frac{0.05}{12})^{12*2}$

$10,000=P(1.0042)^{24}$

$P=10,000/(1.0042)^{24}$

$P=\$9,050.25$

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3 years ago

The circumference of a circle is 28.888 centimeters. What is the circle's radius?

DanielleElmas [232]

Answer:

4.6

Step-by-step explanation:

28.888 / 3.14 = 9.2

9.2 / 2 = 4.6

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3 years ago

Complete the pairs of corresponding parts if AABD = AEFC.<br> B

Anuta_ua [19.1K]

Answer:

see explanation

Step-by-step explanation:

since the triangles are congruent, then corresponding angles are congruent.

∠ B = ∠ F

∠ FCE ≅ ∠ BDA

∠ EFC ≅ ∠ ABD

∠ FEC ≅ ∠ BAD

note that the order of letters in Δ ABD follows the same order as those in Δ BDA

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2 years ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second