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irina [24]
3 years ago
10

1. Evaluate the following expression. Write your answer WITHOUT any exponents. (52)8 x 5-9​

Mathematics
1 answer:
lara31 [8.8K]3 years ago
7 0

Answer:

The answer is 2080x - 9

Hope this helps

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Rewrite the Cartesian equation y=-3 as a polar equation.
andreev551 [17]

r

sin

θ

=

−

3

Explanation:

Imagine we have a point  

P

with Rectangular (also called Cartesian) coordinates  

(

x

,

y

)

and Polar coordinates  

(

r

,

θ

)

.

The following diagram will help us visualise the situation better:

https://keisan.casio.com/exec/system/1223526375

https://keisan.casio.com/exec/system/1223526375

We can see that a right triangle is formed with sides  

x

,  

y

and  

r

, as well as an angle  

θ

.

We have to find the relation between the Cartesian and Polar coordinates, respectively.

By Pythagora's theorem, we get the result

r

2

=

x

2

+

y

2

The only properties we can say about  

θ

are its trigonometric functions:

sin

θ

=

y

/

r

⇒

y

=

r

sin

θ

cos

θ

=

x

/

r

⇒

x

=

r

cos

θ

So we have the following relations:

⎧

⎪

⎨

⎪

⎩

r

2

=

x

2

+

y

2

y

=

r

sin

θ

x

=

r

cos

θ

Now, we can see that saying  

y

=

−

3

in the Rectangular system is equivalent to say

r

sin

θ

=

−

3

Answer link

Jim G.

May 19, 2018

r

=

−

3

sin

θ

Explanation:

to convert from  

cartesian to polar

∙

x

x

=

r

cos

θ

and  

y

=

r

sin

θ

⇒

r

sin

θ

=

−

3

⇒

r

=

−

3

sin

θ

4 0
3 years ago
Consider the vector field.f(x, y, z) = xy2z2i + x2yz2j + x2y2zk(a) find the curl of the vector field.
Marysya12 [62]
First introduce the following notations:
P=yx^2z^2\\Q=x^2yz^2\\R=x^2y^2z\\\text{Then compute the partial derivative like this:}\\R_y=2x^2yz\\Q_z=2x^2yz\\P_z=2yx^2z\\R_x=2xy^2z\\Q_x=2xyz^2\\P_y=x^2z^2\\\text{Then evaluate each of the following:}\\R_y-Q_z=2x^2yz-2x^2yz=0\\P_z-R_x=2yx^2z-2xy^2z=2xyx(x-y)\\Q_x-R_y=2xyz^2-x^2z^2=z^2x(2y-x)\\\text{Our answer will be then:}\\Curl(f)=(2xyx(x-y))j+(z^2x(2y-x))k
7 0
3 years ago
The scale of a map is 1 in. = mi. Find each length on the map
WITCHER [35]

The question gives the relationship to be

1in=21mi

We will interpolate to solve the question.

First Question: 147 mi

\begin{gathered} \text{If 1 in = 21 mi} \\ x\text{ in = 147 mi} \end{gathered}

Cross multiplying,

undefined

7 0
1 year ago
Which statement is always true?
Goshia [24]
I’m pretty sure A is true <3
6 0
2 years ago
Find the circumference of a circle with a radius of 2.4 m
bagirrra123 [75]

Answer:

15.07964

..................

7 0
2 years ago
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