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Masja [62]
3 years ago
11

15.7/6.28 what is the answer how do you do it

Mathematics
1 answer:
Andrew [12]3 years ago
7 0
Simply divide 15.7 by 6.28 to get 2.5 :) easy peasy pumpkin pie
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3 years ago
3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third
den301095 [7]

Answer:

Consecutive odd integers are 19 , 21 & 23

Step-by-step explanation:

Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

According to the question,

2x + 3(x + 2) = 2(x + 4) + 55

=  > 2x + 3x + 6 = 2x + 8 + 55

Eliminating 2x from both the sides,

=  > 3x + 6 = 63

=  > 3x = 63 - 6 = 57

=  > x =  \frac{57}{3}  = 19

So, the consecutive odd integers are = 19 , 21 & 23.

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2 years ago
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alina1380 [7]

Answer:

22 rounds down to 20 if that is what you are asking

Step-by-step explanation:

You did not finish your question i dont think. 22 DOES round down to 20 though.

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MatroZZZ [7]

Answer:

(9,5)

Step-by-step explanation:

10+8/2=18/2=9

6+4/2=10/2=5

4 0
2 years ago
Which represents a quadratic function? ​
netineya [11]

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b is the answer

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f(x) = ax^2 + bx + c

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Read 2 more answers
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