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arsen [322]
3 years ago
13

Find the height of the cylinder whose volume is 1.54m^3 and diameter of the base is 140cm

Mathematics
1 answer:
Gemiola [76]3 years ago
3 0

Answer:

0.7 m or 70 cm

Step-by-step explanation:

We are given;

  • Volume of a cylinder as 1.54 cm³
  • Diameter of the base as 140 cm

We are required to determine the height of the cylinder

We need to know how to find the volume of a cylinder.

Volume of a cylinder is given by the formula;

Volume = πr²h

r = d/2 = 70 cm

But, 100 cm = 1 m

thus, radius = 0.7 m

Rearranging the formula;

H = Volume ÷ πr²

  = 1.54 m³ ÷ (22/7 × 0.7²)

   = 0.7 m

Thus, the height of the cylinder is 0.7 m or 70 cm

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Dave rented a limousine for his wife's birthday. The hourly rate is $70. They used the limousine for 4 hours, plus Dave gave the
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3 years ago
Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

  • \sin{\theta} < \cos{\theta} if 0^{\circ} < \theta;
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  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

4 0
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Jill Barley obtained a 25-year, $60,000.00 mortgage loan from University
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Answer:

a. Interest = $300

b. Payment to principal = $86.40

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Step-by-step explanation:

The monthly payment has both an interest component and a principal repayment component.

The interest component is based on the total principal still due at the time and the principal repayment component will be the rest of the payment.

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