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Sidana [21]
2 years ago
5

Plz help I need it or I’m gonna fail this test

Mathematics
1 answer:
quester [9]2 years ago
4 0

Answer:

-2

Step-by-step explanation:

I think this is the answer

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A researcher wishes to​ estimate, with 9090​% ​confidence, the proportion of adults who have​ high-speed Internet access. Her es
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Answer:  a) Required minimum sample size= 219

b) Required minimum sample size= 271

Step-by-step explanation:

As per given , we have

Margin of error : E= 5% =0.05

Critical z-value for 90% confidence interval : z_{\alpha/2}=1.645

a) Prior estimate of true proportion: p=28%=0.28

Formula to find the sample size :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.28(1-0.28)(\dfrac{1.645}{0.05})^2\\\\=218.213856\approx219

Required minimum sample size= 219

b) If no estimate of true proportion is given , then we assume p= 0.5

Formula to find the sample size :-

n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.645}{0.05})^2\\\\=270.6025\approx271

Required minimum sample size= 271

8 0
2 years ago
Solve the variable in the following proportion. 3.6/y=1.2/2
Molodets [167]
Hello : 
<span>3.6/y=1.2/2
1.2 y = 2(3.6)
y = 2(3.6)/1.2
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7 0
3 years ago
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sergejj [24]
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3 years ago
Find a common denominator for the pair of fractions.​ Then, write equivalent fractions with the common denominator.
DerKrebs [107]
4/12? It may be wrong, not sure
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If two angles of a triangle each measure 50 degrees, then what is the measure of the third angle of the triangle? Complete the s
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Answer: 80

Step-by-step explanation:

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2 years ago
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