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horsena [70]
3 years ago
7

Part B what are the probabilities of each outcome in the sample space? select all that apply

Mathematics
1 answer:
zepelin [54]3 years ago
7 0

Answer:

C, D, and E are correct

Step-by-step explanation:

p(2)= 1/6; p(3)= 1/6; p(4)= 1/6; 1/6=1/6=1/6

p(1)= 3/6; 3/6=1/2

p(4) = 1/6; There are six sections and one section is labeled<em> '4' </em>

<em />

Hope this helped! ;p

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A bacteria colony increases in size at a rate of 4.0581e1.6t bacteria per hour. If the initial population is 36 bacteria, find t
Harrizon [31]

Answer:

1560

Step-by-step explanation:

The rate of Increase of the population (P) of the bacteria is given as:

\frac{dP}{dt} =4.058e^{1.6t}

dP =4.058e^{1.6t}}dt\\Taking\: Integrals\\\int dP =4.058 \int e^{1.6t}dt\\P(t)=\frac{4.058}{1.6} (e^{1.6t} +K)\\P(t)=2.53625 (e^{1.6t} +K)

Where k is a constant of Integration.

At t=0, P(t)=36

36=2.53625 (e^{1.6*0} +K)\\36=2.53625 (e^{0} +K)\\36=2.53625 (1 +K)\\36=2.53625 +2.53625K\\K=13.19

Therefore:

P(t)=2.53625 (e^{1.6t} +13.19)\\At \: t=4\\P(4)=2.53625 (e^{1.6*4} +13.19)\\=1559.88\\P(4)=1560

3 0
3 years ago
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3 years ago
Evaluate the function
Sedaia [141]

f(0) =  {4}^{3 \times 0  + 3}  =  {4}^{0 + 3}  =  {4}^{3}  = 64
The answer is above.
Additional note 1:
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Additional note 2:
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3 0
3 years ago
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5. A yacht is cruising at 20 knots at bearing of 185° when a 15 knot wind starts to blow at a bearing of 290°. Find the directio
kicyunya [14]

Answer:

<em>Direction of the boat is 43.05° and the speed is 21.66 knot</em>

<em></em>

Step-by-step explanation:

yacht speed = 20 knots

yacht bearing = 185° = 85°  below the negative horizontal x-axis

wind speed = 15 knots

wind bearing = 290° = 20° above the negative horizontal x-axis

we find the x and y components of the boat velocities

for yacht,

x component = -20 cos 85° = -1.74 knots

y component = -20 sin 85° = -19.92 knots

for the wind,

x component = -15 cos 20° = -14.09 knots

y component = 15 sin 20° = 5.13 knots

total x component  Vx = -1.74 + (-14.09) = -15.83 knots

total y component Vy =  -19.92 + 5.13 = -14.79 knots

Resultant speed of the boat = \sqrt{Vx^{2} + Vy^{2}  }

==> \sqrt{15.83^{2} + 14.79^{2}  } = <em>21.66 knot</em>

<em></em>

direction of boat = tan^{-1} \frac{Vy}{Vx}

==> tan^{-1} \frac{14.79}{15.83} = <em>43.05°</em>

3 0
3 years ago
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