2/7 = 4/5 + 1/7 q answe for q

Mathematics

1 answer:

Alchen [17]2 years ago

7 0

Answer:

Step-by-step explanation:

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Which values from the given replacement set make up the solution set of the inequality? 2b≥6;

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2 years ago

1. What is the slope between the points (2,-5) and (8,3)? *<br><br> Show work please

hjlf

Answer:

$\sf m = \dfrac{4}{3}$

Step-by-step explanation:

Given, $\sf (x_1, ~ y_1)$ = (2, -5) and $\sf (x_2, ~ y_2)$ = (8, 3)

The slope formula is, $\sf m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$\sf m = \dfrac{3 - (-5)}{8 - 2}$

$\sf m = \dfrac{8}{6}$

$\bf m = \dfrac{4}{3}$

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Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m

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Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of $t_{ \frac{1}{2} }$ after t years is given by

$N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }$

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

$18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\ \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\ \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\ \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4$

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>

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