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Radda [10]
3 years ago
15

How do you turn a inproper mixed fraction proper

Mathematics
2 answers:
Arisa [49]3 years ago
4 0
Divide the numerator by the denominator.
Write down the whole number answer.
Then write down any remainder above the denominator.
11111nata11111 [884]3 years ago
3 0
EXAMPLE: Turning 4/3 into an improper fraction
In order to turn an improper fraction into a mixed fraction, you need to find the closest number to multiply the denominator by to get the numerator (ex: 3 times 1 is the closest number to 4). Then you would subtract that number after it was multiplied (in this case 1x3= 3) from the original numerator (so 4-3 = 1.) The answer for this question is 1 and 1/3.
Another example: 15/4 is 3 and 3/4 as a mixed number because 15 divided by 4 is closest to 3 (3x4 is 12 and 3x5 is 15, which is too large) with a remainder of 3. The closest multiple is the whole number and the remainder is the new numerator.
Hope this helps! I'm sorry if it's confusing-- it's easier to explain with paper and pencil :)
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Which is the best approximation for the value of 160−−−√?
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Some liquid will be poured from a 16 ounce container until it is filled to the percent of the the larger container (87.5%).How m
4vir4ik [10]

Answer:

16 ounces

Step-by-step explanation:

First we are told that a container has a capacity of 16 ounces of liquid and therefore 16 ounces of liquid can fill that one container

The 16 ounces liquid from the 16 ounce container is fully emptied in a larger container and fills 87.5% of the larger container therefore the larger container is:

100/87.5×16 ounces= 18.285 ounces in liquid capacity

Therefore to fill the smaller 16 ounce container, the larger container would have to pour 16 ounces of liquid into the smaller container, and would would still have 18.285-16=2.285 ounces if it(the larger container) were filled to the brim(100%)

8 0
3 years ago
Adam has 412 weeks to write 12 papers for school. If he spends an equal amount of time on each paper, how much time will it take
jarptica [38.1K]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
If you are given a3=2 a5=16, find a100.
ra1l [238]

I suppose a_n denotes the n-th term of some sequence, and we're given the 3rd and 5th terms a_3=2 and a_5=16. On this information alone, it's impossible to determine the 100th term a_{100} because there are infinitely many sequences where 2 and 16 are the 3rd and 5th terms.

To get around that, I'll offer two plausible solutions based on different assumptions. So bear in mind that this is not a complete answer, and indeed may not even be applicable.

• Assumption 1: the sequence is arithmetic (a.k.a. linear)

In this case, consecutive terms <u>d</u>iffer by a constant d, or

a_n = a_{n-1} + d

By this relation,

a_{n-1} = a_{n-2} + d

and by substitution,

a_n = (a_{n-2} + d) + d = a_{n-2} + 2d

We can continue in this fashion to get

a_n = a_{n-3} + 3d

a_n = a_{n-4} + 4d

and so on, down to writing the n-th term in terms of the first as

a_n = a_1 + (n-1)d

Now, with the given known values, we have

a_3 = a_1 + 2d = 2

a_5 = a_1 + 4d = 16

Eliminate a_1 to solve for d :

(a_1 + 4d) - (a_1 + 2d) = 16 - 2 \implies 2d = 14 \implies d = 7

Find the first term a_1 :

a_1 + 2\times7 = 2 \implies a_1 = 2 - 14 = -12

Then the 100th term in the sequence is

a_{100} = a_1 + 99d = -12 + 99\times7 = \boxed{681}

• Assumption 2: the sequence is geometric

In this case, the <u>r</u>atio of consecutive terms is a constant r such that

a_n = r a_{n-1}

We can solve for a_n in terms of a_1 like we did in the arithmetic case.

a_{n-1} = ra_{n-2} \implies a_n = r\left(ra_{n-2}\right) = r^2 a_{n-2}

and so on down to

a_n = r^{n-1} a_1

Now,

a_3 = r^2 a_1 = 2

a_5 = r^4 a_1 = 16

Eliminate a_1 and solve for r by dividing

\dfrac{a_5}{a_3} = \dfrac{r^4a_1}{r^2a_1} = \dfrac{16}2 \implies r^2 = 8 \implies r = 2\sqrt2

Solve for a_1 :

r^2 a_1 = 8a_1 = 2 \implies a_1 = \dfrac14

Then the 100th term is

a_{100} = \dfrac{(2\sqrt2)^{99}}4 = \boxed{\dfrac{\sqrt{8^{99}}}4}

The arithmetic case seems more likely since the final answer is a simple integer, but that's just my opinion...

3 0
2 years ago
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