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Radda [10]
2 years ago
15

How do you turn a inproper mixed fraction proper

Mathematics
2 answers:
Arisa [49]2 years ago
4 0
Divide the numerator by the denominator.
Write down the whole number answer.
Then write down any remainder above the denominator.
11111nata11111 [884]2 years ago
3 0
EXAMPLE: Turning 4/3 into an improper fraction
In order to turn an improper fraction into a mixed fraction, you need to find the closest number to multiply the denominator by to get the numerator (ex: 3 times 1 is the closest number to 4). Then you would subtract that number after it was multiplied (in this case 1x3= 3) from the original numerator (so 4-3 = 1.) The answer for this question is 1 and 1/3.
Another example: 15/4 is 3 and 3/4 as a mixed number because 15 divided by 4 is closest to 3 (3x4 is 12 and 3x5 is 15, which is too large) with a remainder of 3. The closest multiple is the whole number and the remainder is the new numerator.
Hope this helps! I'm sorry if it's confusing-- it's easier to explain with paper and pencil :)
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Archy [21]

Answer:

Step-by-step explanation:

If base of variable is same, add the powers

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2) -2n² * -n⁴ * 5n³ = (-2* -1*  5 ) *n²⁺⁴⁺³ = 10n⁹

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3 years ago
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|5x|-2=18 helps love this problem please help
drek231 [11]

Answer:

x = 4

Step-by-step explanation:

The absolute value of 5x is still 5x.

5x - 2 = 18

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Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of
steposvetlana [31]

Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way

Step-by-step explanation:

  • From a standard deck of cards, one card is drawn. What is the probability that the card is black and a jack? P(Black and Jack)  P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
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P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13

  • WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the  probability that they will both be aces?

P(AA) = (4/52)(3/51) = 1/221.

  • WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a  king?

P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been  removed.

  • WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick  a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the

probability of drawing the first queen which is 4/52.

  • The probability of drawing the second queen is also  4/52 and the third is 4/52.
  • We multiply these three individual probabilities together to get P(QQQ) =
  • P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
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