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2 years ago

Easy points!!!!!!!!!!1

Mathematics

2 answers:

Gennadij [26K]2 years ago

8 0

Answer:

986,388 is the answer

Whitepunk [10]2 years ago

3 0

Hello the answer to your question is:

986388

Have a great day!~

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A line goes through the point (2, 4) and has a slope of 3/2. Which of the following points is also on the line? CHOOSE ALL THAT

Korolek [52]

Hmmmm not sure

Explanation: I took this test and got it correct

8 0

3 years ago

The price of 7 cell phones, 9 TV sets and 12 air-conditioners is

mezya [45]

here, 7 cellphone,9 Tv, 12airconditioners = 8723

5 cellphone,7 Tv, 12airconditioners = 6523

or, 7,9,12=8723

-5,7,9=6523

______________

2,2,3=2191

then,

to make 4 cellphone , 4 tv set , 6 air conditioners add twice the answer ,

2,2,3=2191

+2,2,3=2191

____________

4,4,6=4382

hence,

the price of 4 cellphone , 4 tv set and 6 air conditioners is 4382 #

solved by

<h3> pratik</h3>

6 0

3 years ago

What number would you add to both sides of x2 + 7x = 4 to complete the square? A.2^2 B.7^2 C, 7^2/2 D.(7/2)^2

Lostsunrise [7]

The answer is d. (7/2)^2

7 0

3 years ago

Hi I have my answer in I’m just confused and think it’s gonna be wrong so could u guys help me

Masteriza [31]

Answer:

I believe the first one is rotation And the second is ABC= DEF.

Step-by-step explanation:

My geometry is really rusty so I apologize if they’re wrong

8 0

2 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

3 years ago