Hello!
To find the equation of a line parallel to y = 3x - 3 and passing through the point (4, 15), we need to know that if two lines are parallel, then their slopes are equivalent.
This means that we create a new equation in slope-intercept form, which includes the original slope, which is equal to 3.
In slope-intercept form, we need a y-intercept. So, we would substitute the given ordered pair into the new equation with the same slope and solve.
Remember that slope-intercept form is: y = mx + b, where m is the slope and b is the y-intercept.
y = 3x + b (substitute the ordered pair (4, 15))
15 = 3(4) + b (simplify)
15 = 12 + b (subtract 12 from both sides)
3 = b
Therefore, the equation for the line parallel to the line y = 3x - 3, and passing through the point (4, 15) is y = 3x + 3.
Answer: Y= - 1/2x - 8
If you move y to one side by itself that’s what you’ll get and you can check this answer by multiplying each side by 2 and moving the x ti the left side and you’ll get your beginning equation
If it not right feel free to comment and tell me
A 4x25=100 10x10=100 making 100 a common multiple of 4 and 10.
Answer:
Step-by-step explanation:
Since 1pt = 2qt, 2.75pt = 5.5qt
