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3 years ago

8

Help please...............

1 answer:

USPshnik [31]3 years ago

6 0

Answer:

A warrior is a person specializing in combat or warfare, especially within the context of a tribal or clan-based warrior culture society that recognizes a separate warrior class or caste.

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I need help solving them and quick cause I don’t have a lot of time

riadik2000 [5.3K]

A: x = 2.4
b: m = 9.6
c: c = 2 5/12
d: m = 3.6
e: c = 6.6

7 0

3 years ago

Rob who has 13 girls phone number that are in his homeroom has 3 more than half the number that jay has what is the algebraic eq

Vikki [24]

Well Jay has 20 phone numbers.
20j=13r-3x2 im not sure but i hope that helped a little.

8 0

3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0

3 years ago

Read 2 more answers

How can I solve this question???

eduard

Answer:

144°

Step-by-step explanation:

step 1

Find the measure of the central angle of the regular pentagon

Divide 360 degrees by 5 (the number of sides)

$360\°/5=72\°$

Let

c----> the center of the pentagon

we know that

m∠ECA=72°

m∠ACB=72°

therefore

m∠ECB=m∠ECA+m∠ACB

substitute the values

m∠ECB=72°+72°=144°

The measure of angle ECB is equal to the degrees that the pentagon rotate

5 0

3 years ago

Five angles of a hexagon measures 119, 129,104,139 and 95 degrees. What is the measure of the sixth angle?

Kisachek [45]

Answer:

x = 134

Step-by-step explanation:

Given that,

Five angles of a hexagon measures 119, 129,104,139 and 95 degrees.

We know that,

The sum of interior angles of a hexagon must equal 720 degrees.

So,

119+129+104+139 +95+x = 720

Where

x is the sixth angle

So,

586+x=720

x = 720-586

x = 134

So, the sixth angle is equal to 134.

5 0

3 years ago