Answer: The required equation is 
and the number of fishes in the pond on June 1 = 115
Step-by-step explanation:
Given: The number of fishes in pond on July 1 = 63
Also, it is said that the number of fishes in pond on July 1 is 52 fewer(lesser) than the number of fishes in pond on June 1.
Let f be the number of fishes in pounds on June 1.
then the required equation will be
Now, add 52 on both the sides of the equation, we get
Answer:
Not sure if this is correct but this is what I found.
area of sector=74.84
radius = 8
angle of sector=?
74.84=1/2×8²×angle of sector
74.84=32 × angle of sector
74.84/32= angle of sector
2.33875=angle of sector
Step-by-step explanation:
Sorry if it is incorrect.
Answer:
A) sin θ = 3/5
B) tan θ = 3/4
C) csc θ = 5/3
D) sec θ = 5/4
E) cot θ = 4/3
Step-by-step explanation:
We are told that cos θ = 4/5
That θ is the acute angle of a right angle triangle.
To find the remaining trigonometric functions for angle θ, we need to find the 3rd side of the triangle.
Now, the identity cos θ means adjacent/hypotenuse.
Thus, adjacent side = 4
Hypotenuse = 5
Using pythagoras theorem, we can find the third side which is called opposite;
Opposite = √(5² - 4²)
Opposite = √(25 - 16)
Opposite = √9
Opposite = 3
A) sin θ
Trigonometric ratio for sin θ is opposite/hypotenuse. Thus;
sin θ = 3/5
B) tan θ
Trigonometric ratio for tan θ is opposite/adjacent. Thus;
tan θ = 3/4
C) csc θ
Trigonometric ratio for csc θ is 1/sin θ. Thus;
csc θ = 1/(3/5)
csc θ = 5/3
D) sec θ
Trigonometric ratio for sec θ is 1/cos θ. Thus;
sec θ = 1/(4/5)
sec θ = 5/4
E) cot θ
Trigonometric ratio for cot θ is 1/tan θ. Thus;
cot θ = 1/(3/4)
cot θ = 4/3
Answer: B. 70
Step-by-step explanation:
i actually can't tell but i think this is right
Answer:
rational
Step-by-step explanation:
