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storchak [24]
3 years ago
11

What does ⊥ mean in math ? plz don't copy from g00gle

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0

Answer:

Perpendicular

Step-by-step explanation:

It is a symbol used for showing any two lines perpendicular to each other.

Jlenok [28]3 years ago
6 0

Answer:

The symbol ⊥ is representative of the perpendicularity of lines.

Step-by-step explanation:

For lines to be perpendicular, they must intersect and form a right angle <em>(90 degrees)</em>.

For example, in the image shown:

AB ⊥ XY

This is because the two lines intersect and form a right angle.

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Answer:

taxi

Step-by-step explanation:

you would take the taxi because it would cost less than Uber

3 0
3 years ago
Mark buys a wooden board that is feet long. The cost of the board is $1.50 per 5 1/4 foot, including tax. What is the total cost
Lelechka [254]
It would just be the tot foot time the cost

7.5 X 0.50 = $3.75
8 0
3 years ago
Are both a function or not ?
Ganezh [65]

Answer:

Here

Step-by-step explanation:

Domain : (-∞,∞)

Range : (-∞,∞)
Both functions generally are the same and yes both are functions.

One is the data set of a function and one is the equation...

Sorry if this isn't what you were looking for...

8 0
2 years ago
The measure of an exterior angle at n measures 99�. m�l � __1 3 x� and m�m � __2 3 x�. find m�l, m�m, and m�lnm.
kirill [66]
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8 0
4 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3&#10;

has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
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