Answer:
glizzy
Step-by-step explanation:
Again u just have to meaiuse
Cylinder Volume
V = hπr²
154 cm³ = 16 cm × 3.14 × r²
154 cm³ = 50.28 cm × r²
r² = 154 cm³ : 50.28 cm
r² = 3.0625 cm²
r = 1.75 cm
d = 2r
d = 2 × 1.75 cm
d = 3.5 cm
So, the diameter of the Cylinder is 3.5 cm
#LearnWithEXO
Step-by-step explanation:
Since ∠E is right angle, its opposite side is DF and the legs are DE and EF.
<u>Pythagorean applied:</u>
Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)