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miskamm [114]
3 years ago
9

The key schedule results in generating multiple keys from the one secret key. These multiple keys are used:

Computers and Technology
1 answer:
Helga [31]3 years ago
3 0

Answer:

Option(d) is the correct answer to the given question .

Explanation:

There are various type of algorithm is used for the purpose of the key scheduling such as AES .in the AES algorithm we used same key for encryption and decryption of text .The  main objective of the AES algorithm it is used by Various round of the similar plain text encryption to reinforce the cipher text.

  • The Option (a) is wrong because In the key scheduling the creating keys are not being used one after just another in the various communication cycles.
  • The Option (b) is wrong because In the key scheduling  we do not used the  the random key for the encryption process .
  • The Option (c) is wrong because we will never arbitrarily subdivided into groups of public and private key.

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Nataly [62]

Answer: There are many types of files because they all serve separate purposes.

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PNG (Portable Network Graphics)- logos, websites photos, social networks (profile pictures, posts, and cover photos).

GIF (Graphics Interchange Format)- short animations for social channels

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6 0
2 years ago
Which of these are examples of an access control system? Check all that apply.
lesya692 [45]

The examples of an access control system include the following:

C. OAuth

D. TACACS+

E. RADIUS

An access control system can be defined as a security technique that is typically designed and developed to determine whether or not an end user has the minimum requirement, permission and credentials to access (view), or use file and folder resources stored on a computer.

In Cybersecurity, an access control system is mainly used to verify the identity of an individual or electronic device on a computer network, especially through authentication and authorization protocols such as:

  • OAuth: Open Authorization.
  • TACACS+: Terminal Access Controller Access Control Server.
  • RADIUS: Remote Authentication Dial-In User Service.

Read more on access control here: brainly.com/question/3521353

8 0
2 years ago
Android OS "AFTER" Alpha.<br><br> A. Bubblegum<br><br> B. Beta<br><br> C. Berry<br><br> D. Buzz Cola
algol13
Alpha is first trial run

Beta usually comes next, with patches and fixes to problems or shortfalls in the Alpha test release

Then more tweaks/fixes comes a full public rollout.

Believe Android release 11.0 beta version testing started in June of 2020.
3 0
3 years ago
Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress 50%, or 2 sec
kozerog [31]

Answer: bandwidth = 0.10 MB/s

Explanation:

Given

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.50 MB / Bandwidth)

Transfer Size = 0.50 MB

Total Time = Compression Time + RTT + (0.50 MB /Bandwidth)

Total Time = 1 s + RTT + (0.50 MB / Bandwidth)

Compression Time = 1 sec

Situation B:

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.40 MB / Bandwidth)

Transfer Size = 0.40 MB

Total Time = Compression Time + RTT + (0.40 MB /Bandwidth)

Total Time = 2 s + RTT + (0.40 MB / Bandwidth)

Compression Time = 2 sec

Setting the total times equal:

1 s + RTT + (0.50 MB / Bandwidth) = 2 s + RTT + (0.40 MB /Bandwidth)

As the equation is simplified, the RTT term drops out(which will be discussed later):

1 s + (0.50 MB / Bandwidth) = 2 s + (0.40 MB /Bandwidth)

Like terms are collected:

(0.50 MB / Bandwidth) - (0.40 MB / Bandwidth) = 2 s - 1s

0.10 MB / Bandwidth = 1 s

Algebra is applied:

0.10 MB / 1 s = Bandwidth

Simplify:

0.10 MB/s = Bandwidth

The bandwidth, at which the two total times are equivalent, is 0.10 MB/s, or 800 kbps.

(2) . Assume the RTT for the network connection is 200 ms.

For situtation 1:  

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 1 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.50 MB

Total Time = 1.2 sec + 5 sec

Total Time = 6.2 sec

For situation 2:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 2 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.40 MB

Total Time = 2.2 sec + 4 sec

Total Time = 6.2 sec

Thus, latency is not a factor.

5 0
3 years ago
X = 9 % 2if (x == 1):  print ("ONE")else:  print ("TWO")
IgorC [24]

Answer:

ONE

Explanation:

It prints one because % is modulus, which is remainder division. It divides the numbers provided and returns the remainder of the division. 9 / 2 = 4 with 1 remainder, which leads us to our answer.

4 0
2 years ago
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