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Paha777 [63]
3 years ago
8

If r is an instance of the above Person class and oddNum has been declared as a variable of type boolean, which of the following

correctly sets oddNum to true if Person object r has an odd number of children and to false otherwise?
oddNum = ( ( r.numChildren() % 2 ) != 0 );

if ( ( r.numChildren() % 2 ) == 0 )

oddNum = false;

else

oddNum = true;

oddNum = false;

for ( int k = 0 ; k < r.numChildren() ; k++ )

oddNum = !oddNum;

I only

II only

III only

I and II only

I, II, and III
Computers and Technology
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

I, II, and III

Explanation:

The three are almost saying the same thing. the loop is one am a bit concerned about. but since the oddnum is set to false, the loop will work.

The one and two are pretty clear. to test for odd number, the easiest is to divide by two to see if there will be a remainder. That is what both first and second statement is trying to do.

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def integer_to_reverse_binary(integer_value):

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integer_to_reverse_binary(integer_value)

Explanation:

This imports the math module

import math

This defines the integer_to_reverse_binary function

def integer_to_reverse_binary(integer_value):

This initializes the remainder to an empty string

   remainder = ""

This loop is repeated while the integer input is greater than or equal to 1

   while integer_value>=1:

This calculates the remainder after the integer value is divided by 2

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This gets the floor division of the integer input by 2

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This passes the remainder to the reverse_string function

   reverse_string(remainder)

The reverse_string function begins here

def reverse_string(input_string):

This initializes the binaryOutput to an empty string

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This iterates through the input string i.e. the string of the remainders

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This reverses the input string

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This prints the binary output

   print(binaryOutput)

<u>The main begins here</u>

This gets input for integer_value

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This passes the integer value to the integer_to_reverse_binary function

integer_to_reverse_binary(integer_value)

3 0
3 years ago
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