The interval that f(x) is increasing is the distance from 200 to 300.
The minimum value of f(x) in the interval 0<x<300 is 200.
At a value of 500, the value of f(x) is 0.
The function can't be a quadratic function since there are two points in the graph where f(x) changes its rate from increasing to decreasing or the opposite. A quadratic function has only one of that point.
Answer:
31.2
Step-by-step explanation:
Answer:
hope this helps! :)
Step-by-step explanation:
Partition the primary number of the profit (or the two first numbers if the past advance took another digit) by the principal digit of the divisor. Compose the consequence of this division in the space of the remainder. Increase the digit of the remainder by the divisor, compose the outcome underneath the profit and deduct it
5
g(f(-5))
g( | 2 * -5 + 9 | )
g( |-1| )
g(1)
5
