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3 years ago

Which angles are vertical angles?

Mathematics

1 answer:

shutvik [7]3 years ago

6 0

Answer:

<DCA and <BCF

Step-by-step explanation:

The vertically opposite angles are the angles <DCA and <BCF. These angles are always equal.

When two lines cross, two angles that are vertical two one another are equal.
They are know as vertically opposite angles.
When two straight lines cross each other, four angles are produced.
The two vertically opposite have the same values.

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UNO [17]

Question 1

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Question 2

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

) Find the coordinates of the point A' which is the symmetric point

soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

$C( \dfrac{x+3}{2}, \dfrac{y+2}{2})$

Also, product of slope will be -1 .( Since, they are parallel )

$\dfrac{y-2}{x-3} \times -2 = -1\\\\2y - 4 = x - 3\\\\2y - x = 1$

x = 2y - 1

So, $C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})$

Also, C satisfy given line :

$2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}$

Also,

$x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}$

Therefore, the symmetric points is $A'(\dfrac{31}{5}, \dfrac{18}{5})$ .

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3 years ago

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vlada-n [284]

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3 years ago

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Gemiola [76]

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Step-by-step explanation:

The probability that it is a blue marble is 3 out of total marbles of 14

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3 years ago