1. 15*10*10= 1500
2*4*4=32
1500-32=1468
So the answer is 1468 in³
So
volume=height times area of base
base =circle so
area of base=area of circle=pir^2
volume=h(pi)r^2
h=12
r=6
pi=3.14 aprox
subsitute
volume=12(3.14)6^2
volume=12(3.14)36
volume=1356.48
that is vol of 1 tank
1356.48 times 5=6782.4
answer is 6782.4 ft^2 or D
There is 4 outcomes per cone/cups so therefore the answer 4*3 which equals 12.
20.89<u>6</u>
The number 3 places after the decimal is the thousandth place.
.8 → tenth place
.8<u>9</u> → hundredths place
.89<u>6</u> → thousandth place
Explanation:
The first step is to figure out what the equation is. When unconventional math symbols are used, and when there are no grouping symbols identifying operands, that can be the most difficult step. Here, we think the equation is supposed to be ...
![\sqrt[3]{x+1}-2=0](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%7D-2%3D0)
It usually works well in radical equations to isolate the radical. Here that would mean adding 2 to both sides of the equation, to undo the subtraction of 2.
![\sqrt[3]{x+1}=2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%7D%3D2)
Now, it is convenient to raise both sides of the equation to the 3rd power.

Finally, we can isolate the variable by undoing the addition of 1. We accomplish that by adding -1 to both sides of the equation.

The equation is solved. The solution is x = 7.