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3 years ago

Expression. 3(4x + 3)

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

5 0

3(4x+3) simplified as an expression is: 12x+9

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What is the actual distance around the garden?It took Clare 30 minutes to walk around the garden at a constant speed

konstantin123 [22]

Answer:

f she walks for 30 minutes, that means she was traveling at about 280 feet per minute (8,400÷30=280), or about 16,800 feet per hour

Step-by-step explanation:

8 0

3 years ago

Solve the following compound inequality <br> 12 < 2x-4/3 < 16 <br> step by step

motikmotik

Answer:

x∈(20/3;26/3)

Step-by-step explanation:

12 < 2x-4/3 < 16

first we add 4/3 to each side

12+4/3<2x<16+4/3

we bring to the same denominator

12*3/3+4/3<2x<16*3/3+4/3

(36+4)/3<2x<(48+4/3)

40/3<2x<52/3

now we divide by 2

20/3<x<26/3

x∈(20/3;26/3)

4 0

3 years ago

Use separation of variables to solve dy dx − tan x = y2 tan x with y(0) = √3. Find the value of c in radians, not degrees

a_sh-v [17]

Answer:

$y(x)=tan(-log(cos(x))+\frac{\pi }{3} )$

Step-by-step explanation:

Rewrite the equation as:

$\frac{dy(x)}{dx}-tan(x)=y(x)^{2} *tan(x)$

Isolating $\frac{dy}{dx}$

$\frac{dy}{dx} =tan(x)+tan(x)*y^{2}$

Factor:

$\frac{dy}{dx} =tan(x)*(1+y^{2} )$

Dividing both sides by $(1+y^{2} )$ and multiplying them by $dx$

$\frac{dy}{1+y^{2} } =tan(x)dx$

Integrate both sides:

$\int\ \frac{dy}{1+y^{2} } = \int\ tan(x) dx$

Evaluate the integrals:

$arctan(y)=-log(cos(x))+C_1$

Solving for y:

$y(x)=tan(-log(cos(x))+C_1)$

Evaluating the initial condition:

$y(0)=\sqrt{3} =tan(-log(cos(0))+C_1)=tan(-log(1)+C_1)=tan(0+C_1)$

$\sqrt{3} =tan(C_1)\\arctan(\sqrt{3} )=C_1\\60=C_1$

Converting 60 degrees to radians:

$60degrees*\frac{\pi }{180degrees} =\frac{\pi }{3}$

Replacing $C_1$ in the diferential equation solution:

$y(x)=tan(-log(cos(x))+\frac{\pi }{3} )$

3 0

3 years ago

BRAINLIEST IF CORRECT!!!

LenKa [72]

Answer:

X=1

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Given: △ABC, m∠C=90° m∠ABC=30°, AL ∠ bisector CL=6 ft. Find: LB

vlada-n [284]

For a better understanding of the solution given here please go through the diagram in the file attached.

To solve this question we will make use of the "Triangle Angle Bisector Theorem", which states that, "An angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle."

Thus, in our question, we will have:

$\frac{LB}{CL}= \frac{AB}{AC}$