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3 years ago

I need help with q5

Mathematics

1 answer:

Roman55 [17]3 years ago

7 0

Percent increase = ((new number - original number) / (original number)) x 100.

percent increase = ((3000 - 2500) / 2500)) x 100 =
(500 / 2500)....x 100 =
0.2 x 100 =
20% increase <====

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5 qt = ? gal????????

strojnjashka [21]

Answer:

1.25 gal

Step-by-step explanation:

5/4 = 1.25

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3 years ago

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Identify a negative coterminal angle to 480°

Lisa [10]

Step-by-step explanation:

here's the answer to your question

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2 years ago

What are the scale factor of ABC dilated to XYZ plz help

jekas [21]

<h3>Answer: B) 2/3</h3>

====================================

Explanation:

The order is important for ABC and XYZ so we can see what letters pair up.

A pairs with X since they are the first letters
B pairs with Y since they are the second letters
C pairs with Z since they are the third letters

Based on that, we can see that AB pairs with XY as they are the first two letters of ABC and XYZ respectively.

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We could also divide XZ over AC

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and we get the same ratio

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3 years ago

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Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin

NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

2) Confidence interval

Assuming that $\bar X =5.5$ and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=1086-1=1085$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that $t_{\alpha/2}=2.33$

Now we have everything in order to replace into formula (1):

$5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139$

$5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861$

So on this case the 95% confidence interval would be given by (5.139;5.861) We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

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3 years ago

Given the graph below, find PQ

murzikaleks [220]

Answer:

P=(-5,-1)

Q=(2,-4)

Step-by-step explanation:

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