Answer:
The correct answer is 15 cm.
Step-by-step explanation:
Let the width of the required poster be a cm.
We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.
Similarly total margin combining both the sides is (4+4=) 8 cm.
So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } 
This area is equal to 125 as per as the given problem.
∴ (a - 10) × (a - 8) = 125
⇒ 
- 18 a +80 -125 =0
⇒ - 18 a -45 = 0
⇒ (a-15) (a-3) = 0
By law of trichotomy the possible values of a are 15 and 3.
But a=3 is absurd as a 
4.
Thus the required answer is 15 cm.
Actually Welcome to the Concept of the volumes.
Here given as, r= 6.2 mm, h = 10.8 mm, π=3.14
hence, the volume of the cone is
Volume = 1/3(πr^2h)
===> vol = 1/3(3.14*(6.2)^2*(10.8))
==> Vol = 1/3*(1303.57)
==> Vol = 434.52 mm^3
Hence the volume of the cone is 434.52 mm^3
Answer:
0.114,0.5263
Step-by-step explanation:
Given that a firm buys components from two suppliers:
A : 60% Defective 9%
B:40% Defective 15%
a) the probability that the next component the firm buys is defective
=prob purchased from A and defective + prob purchased from B and defective
= 
b) the probability that the component that the firm buys is from supplier B if we know that it is defective
=Prob from B and defective/Prob defective
= 
Your answer would be B.
Hope this helps.
