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Komok [63]
3 years ago
9

A researcher took a random sample of 100 students from a large university. She computed a 95% confidence interval to estimate th

e average weight of the students at this university. The confidence interval was too wide to provide a precise estimate. True or false
Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer: False

Step-by-step explanation:

All the 100 students engaged in the experiment were picked on the basis that all the students of the university have a chance of being selected. The selected participants must have represented the whole university well.

So, having a 95% confidence interval that the experiment might have atmost 5% error prone is statistically enough and not too wide to give an accurate estimate.

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Can I get help with this
Marta_Voda [28]

Answer:

X = 60

Y = 50

Step-by-step explanation:

The total degrees of a triangle is 180 degrees. For the middle triangle, 50+70=120 so 180-120=60.

On the far right, Y=50 because you take 50 degrees from the middle triangle, and insert it there.

3 0
3 years ago
Round 325.49 to the nearest tens place
VLD [36.1K]
If you meant tens place it's 330 if you meant tenths place it's 325.5
6 0
3 years ago
Read 2 more answers
For the arthritic sequence 5,9,13,17,21,... how many terms would you need to get to 129
Vlad1618 [11]

9514 1404 393

Answer:

  32

Step-by-step explanation:

The first term is 5 and the common difference is 9-5=4, so the n-th term is ...

  an = a1 +d(n -1)

  an = 5 +4(n -1) = 4n +1

Then the term number for the term 129 is ...

  129 = 4n +1 . . . . . put the given value in the formula

  128 = 4n  . . . . . . . subtract 1

  32 = n . . . . . . . . . .divide by 4

The 32nd term is 129.

8 0
3 years ago
Mr. Nichols put $1,200 in a savings account at a local bank. The simple annual interest rate was 5%. How much interest did his a
satela [25.4K]

\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad  \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\to& \$1200\\ r=rate\to 5\%\to \frac{5}{100}\to &0.05\\ t=years\to &3 \end{cases} \\\\\\ I=(1200)(0.05)(3)\implies I=180

8 0
3 years ago
Solve -vp+40<95 for v
Leya [2.2K]

-vp+40<95

subtract 40 from each side

-vp < 55

divide by -p (which flips the inequality) assuming p>0

v > -55/p


5 0
3 years ago
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