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LiRa [457]
3 years ago
5

If one zero of the polynomial (a^2+9)x^2+13x+6a is the reciprocal of the other, find the value of a.​

Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer: a^2x^2+9x^2+13x+6a

Step-by-step explanation:

(a^2+9) x^2+ 13x +6a

x^2(a^2+9)+13x+6a

Expand:x^2(a^2+9): a^2 x^2+9^2

x^2 a^2 +x^2*9

a^2 x^2+9x^2

  a^2 x^2+9x^2+13x+6a

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What’s 1/6 plus 3/8 in simplest form
gregori [183]

13/24 is the answer to your problem.


7 0
3 years ago
Evaluate the following expression for x=-2 -4x+8+2x+3
sergiy2304 [10]

Answer:

15

Step-by-step explanation:

x = 2

-4x+8+2x+3 = ?

-4 (-2) + 8 + 2 (-2) + 3 =

= 8 + 8 - 4 + 3

= 16 - 4 + 3

= 12 + 3

= 15

hopefully this helped you :)

8 0
3 years ago
-4.8=1.2s+2s+4<br><br><br>Please help me <br>​
nikdorinn [45]
Simplify both sides of the equation
-4.8=1.2s+2s+4
Combine like terms
-4.8=(1.2s+2s)+(4)
-4.8=3.2s+4
Flip the equation
3.2s+4=-4.8
Subtract both sides by 4
3.2s+4-4=-4.8-4
3.2s=-8.8
Divide both sides by 3.2
3.2s/3.2= -8.8/3.2
S=-2.75 will be the answer hope it helps
6 0
3 years ago
Can you please help me
viva [34]
There are fewer people on the bus.
The start of it had at least 5
The end of it had at least 1
8 0
3 years ago
Read 2 more answers
What is the measure of arc CD?
CaHeK987 [17]

Option C:

The measure of arc CD is 40°.

Solution:

Given data:

m∠X = 11° and m(arc AB) = 18°

To find the measure of arc CD:

We know that,

<em>Angle formed by two intersecting secants outside the circle is equal to half of the difference between the intercepted arcs.</em>

$m \angle X =\frac{1}{2}({arc  \ CD}-{arc}  \ AB)

$ 11^\circ =\frac{1}{2}({arc}  \ CD-{18^\circ})

Multiply by 2 on both sides.

22° = arc CD - 18°

Add 18° from both sides.

40° = arc CD

Switch the sides.

arc CD = 40°

Hence the measure of arc CD is 40°.

Option B is the correct answer.

7 0
3 years ago
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