When multiplying the same base with exponents, you keep the base the same and then you add the exponents, so for this question you do:
10^3 x 10^6
10^9
Divide the first equation by 2 and add the result to the second equation. This will eliminate x.
... (-4x -2y)/2 + (2x +4y) = (-12)/2 +(-12)
... 3y = -18 . . . . . collect terms
... y = -6 . . . . . . . divide by 3
Substitute this into either equation to find x. Let's use the second equation, where the coefficient of x is positive.
... 2x +4(-6) = -12
... 2x = 12 . . . . . . . . add 24
... x = 6 . . . . . . . . . . divide by 2
The solution is (x, y) = (6, -6).
Step-by-step explanation:
Given equations
2x + 5y = 6 .......i)
2x = 10 - 3y...... II)
Putting 2x = 10 - 3y in equation i
10 - 3y + 5y = 6
2y = 6 - 10
2y = - 4
y = - 4 / 2
y = - 2
Now putting y = - 2 in equation ii
2x = 10 - 3 * ( - 2)
2x = 10 + 6
2x = 16
x = 16 / 2
x = 8
So x = 8 and y = - 2
Hope it will help :)❤
