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2 years ago

Solve -7 + p = 3 for p. 10 -4 4 -10

Mathematics

2 answers:

Naily [24]2 years ago

4 0

Answer:

Step-by-step explanation:

Solve for p:

p - 7 = 3

Hint: | Isolate terms with p to the left hand side.

Add 7 to both sides:

p + (7 - 7) = 7 + 3

Hint: | Look for the difference of two identical terms.

7 - 7 = 0:

p = 3 + 7

Hint: | Evaluate 3 + 7.

3 + 7 = 10:

Answer: p = 10

r-ruslan [8.4K]2 years ago

4 0

Hey there!☺

$Explanation:$

Solve for p | $-7+p=3$

In step 1, we will simplify both sides of the equation:

$p-7=3$

In step 2, we will add 7 to both sides:

$p-7+7=3+7\\p=10$

p=10 is your answer.

Hope this helps!☺

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An elliptical culvert is 3.5 feet tall and 6 feet wide. It is filled with water to a depth of 0.95 feet. Find the width of the s

maks197457 [2]

Answer:

$W_s \approx5.3$

Step-by-step explanation:

From the question we are told that

Height $H=3.5ft$

Weight $W= 6ft$

Depth $D=0.95ft$

Generally the equation for ellipses is given as

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

Where

$b=H/2\\b=3.5/2\\Therefore\\b=1.75\\a=W/2\\a=6/2\\Therefore\\a=3\\$

$\frac{x^2}{3^2} +\frac{y^2}{1.75^2} =1$

Generally to find y in the equation $\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

$y=-b+d$

$y=-1.75+0.95$

$y=-0.8$

Therefore

$\frac{x^2}{3^2} +\frac{(0.8)^2}{1.75^2} =1$

$\frac{x^2}{3^2} =1-\frac{(0.8)^2}{1.75^2}$

$\frac{x^2}{3^2} =1-0.2089795918$

$X^2 =3^2(1-0.2089795918)$

$X^2 =7.119183674$

$X =\sqrt{7.119183674}$

$X =2.66817984$

Therefore the width of the given stream is

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$W_s=5.33635968$

$W_s \approx5.3$

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2 years ago

Suppose that 4 fair coins are tossed. Let Equals The event that exactly 2 coins show tails and Equal The event that at least 2 c

faust18 [17]

Answer:

a) P ( E | F ) = 0.54545

b) P ( E | F' ) = 0

Step-by-step explanation:

Given:

- 4 Coins are tossed

- Event E exactly 2 coins shows tail

- Event F at-least two coins show tail

Find:

- Find P ( E | F )

- Find P ( E | F prime )

Solution:

- The probability of head H and tail T = 0.5, and all events are independent

So,

P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375

P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)

= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875

- The probabilities for each events are:

P ( E ) = 0.375

P ( F ) = 0.6875

- The Probability to get exactly two tails given that at-least 2 tails were achieved:

P ( E | F ) = P ( E & F ) / P ( F )

P ( E | F ) = 0.375 / 0.6875

P ( E | F ) = 0.54545

- The Probability to get exactly two tails given that less than 2 tails were achieved:

P ( E | F' ) = P ( E & F' ) / P ( F )

P ( E | F' ) = 0 / 0.6875

P ( E | F' ) = 0

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forsale [732]

Answer:

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