To find the sum of an infinite geometric series having ratios with an absolute value less than one, use the formula, S=a11−r, where a1 is the first term and r is the common ratio.
If we let x and y represent length and width, respectively, then we can write equations according to the problem statement.
.. x = y +2
.. xy = 3(2(x +y)) -1
This can be solved a variety of ways. I find a graphing calculator provides an easy solution: (x, y) = (13, 11).
The length of the rectangle is 13 inches.
The width of the rectangle is 11 inches.
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Just so you're aware, the problem statement is nonsensical. You cannot compare perimeter (inches) to area (square inches). You can compare their numerical values, but the units are different, so there is no direct comparison.
49
Because 7x7 is 49 & 4+9=13
Answer:
Lateral surface area of can = 47 inch² (Approx.)
Step-by-step explanation:
Given:
Diameter of given can = 3 inches
Height of given can = 5 inches
Find:
Lateral surface area of can
Computation:
Radius of can = 3 / 2 = 1.5 inch
Lateral surface area of can = Lateral surface area of cylinder
Lateral surface area of cylinder = 2πrh
Lateral surface area of can = 2πrh
Lateral surface area of can = 2(3.14)(1.5)(5)
Lateral surface area of can = 47.1
Lateral surface area of can = 47 inch² (Approx.)
83, the only number between 78 and 88 that has a 3 in the ones place.
Hope this helps!