Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
The absolute value is always non-negative!
So the absolute value of 57 is 57 itself, as it's non-negative (i.e. it's positive or 0).
Opposite value is the number with a different sign: an opposite value of a positive number is negative, so here it will be -57 .
The correct answer is C.
Correct answer is D).
A) and C) are polynomials, so x∈R, in B) we have √x, and in this case x ≥ 0.
Answer:
Yes it does answer A_____
if we name that part x, then we can say
1/x = 1/a + 1/b
