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2 years ago

Graph the following function in picture

Mathematics

1 answer:

irakobra [83]2 years ago

7 0

Answer:

You already have the equations ready so I will just explain

Step-by-step explanation:

The first equation: place a point on the y-axis on -5. then proceed to place points by going down 2 and right 1 or by going up 2 and left 1. that will make your first line.

second equation: on the y-axis place a point on -1 then proceed to go up 1 right 1 or down 1 left 1. that makes your second line

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Naddik [55]

Answer:

$21a^4+4a^2+2a$

Step-by-step explanation:

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3 years ago

How can you the unit rate on a graph that goes through the origin ?

Nonamiya [84]

It must be about the origin in order to do that

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3 years ago

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patriot [66]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Please help, will mark brainliest if correct!!!

Hatshy [7]

Answer:8.5

Step-by-step explanation:

Pythagorean Theorem

a^2 + b^2 = c^2

3^2 + 8^2 = c^2

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6 0

3 years ago

Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of

ioda

Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that $A(24) = (1-0.26)A(0) = 0.74A(0)$ ; We use this to find r.

$A(t) = A(0)(1-r)^t$

$0.74A(0) = A(0)(1-r)^{24}$

$(1-r)^{24} = 0.74$

$\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}$

$1 - r = (0.74)^{\frac{1}{24}}$

$1 - r = 0.9875$

$r = 1 - 0.9875 = 0.0125$

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that $A(0) = 810$

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

$A(t) = A(0)(1-r)^t$

$A(t) = 810(1 - 0.26)^t$

$A(t) = 810(0.74)^t$

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

5 0

3 years ago