Answer:
1 foot and 8.5 inches
Step-by-step explanation:
record: 17ft 8.25 in
yours: 15ft 11.75in +.5 in = 16 ft .25 in
now that yours is 16 ft and .25 inches all you have to add is 1ft and 8 inches which adds up to be 1ft and 8.50 inch
1) Graphing- If you graph the numbers you will easily be able to identify the answer.
2) Substitute- Substitute numbers in for x or y until they're equal on both sides.
EX: 2x+2=10
Substitute numbers in until you get a number that makes it equal on both sides
x= 4
3) Elimination- Eliminate numbers from both sides until they're equal.
Hope this helped! :)
Complete question :
According to the National Association of Realtors, it took an average of three weeks to sell a home in 2017. Suppose data for the sale of 39 randomly selected homes sold in Greene County, Ohio, in 2017 showed a sample mean of 3.6 weeks with a sample standard deviation of 2 weeks. Conduct a hypothesis test to determine whether the number of weeks until a house sold in Greene County differed from the national average in 2017. Useα = 0.05for the level of significance, and state your conclusion
Answer:
H0 : μ = 3
H1 : μ ≠ 3
Test statistic = 1.897
Pvalue = 0.0653
fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.
Step-by-step explanation:
Given :
Sample size, n = 40
Sample mean, x = 3.6
Population mean, μ = 3
Standard deviation, s = 2
The hypothesis :
H0 : μ = 3
H1 : μ ≠ 3
The test statistic :
(xbar - μ) ÷ (s/√n)
(3.6 - 3) / (2/√40)
0.6 / 0.3162277
Test statistic = 1.897
Using T test, we can obtain the Pvalue from the Test statistic value obtained :
df = n - 1; 40 - 1 = 39
Pvalue(1.897, 39) = 0.0653
Decison region :
If Pvalue ≤ α ; Reject the null, if otherwise fail to reject the Null.
α = 0.05
Pvalue > α ; We fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.
Answer:
b
Step-by-step explanation:
