Question

) A class consists of 66 women and 98 men. if 2 students are selected what is the probability they will both be male?

Answer 1

Answer:

98/164 or 0.60

Step-by-step explanation:

p( picking 2 males)

66 females+98 males= 164

=98/164

98 divided by 164= 0.59756097561

0.59756097561= 0.60

( thank me)

Answer 2

Answer: 0.3556 or 35.56%

Step-by-step explanation:

the probability of picking a male the first time is $\frac{num males}{total}$

num males = 98

total = 98 + 66 = 164

so the probability the first time is $\frac{98}{164}$

the probability the second time is $\frac{num males}{total}$

since you already picked a male the first time, num males and total decrease by 1

num males = 98 -1 = 97

total = 164 - 1 = 163

probability the second time is $\frac{97}{163}$

now multiply the probabilities of both times to get the final probability

$\frac{98}{164}$*$\frac{97}{163}$=$\frac{4753}{13366} =0.3556=35.56%$%